9/3c=300/100c
That factors to (b + 3)(a + c)
If for the two integers a + b = c, a is larger than zero and b is larger than the absolute value of the first number, then c is always positive. If a is smaller than zero, and b is larger than the absolute value of the second number, then c is positive. If a is smaller than zero, and b is smaller than the absolute value of the second number, then c is negative.
The equation for converting *F to *C is: *C= (5/9)(*F - 32) So, 90*F into *C would be: *C= (5/9)(90-32) = (5/9)(58) = 32.22*C
Use the formula (F - 32)/9 = C/5 Thus (105 -32)/9 = C/5 73/9 = C/5 I am sure you can calculte the value of C, try it, Good luck!
) Define two functions that convert temperatures between degrees Fahrenheit and degrees Celsius. C= (F+40)* 5/9 -40 F= (C+40)* 9/5 -40 > (defun f-to-c (f)(- (/ (* (+ f 40) 5) 9) 40)) > (defun c-to-f (c)(- (/ (* (+ c 40) 9) 5.0) 40))
If you mean: -12 = 3c-9 then c works out as -1
4c+2 = 3c+9 4c-3c = 9-2 c = 7
3c(squared)-17c-6 = 0 (3c+1)(c-6) = 0 c= negative one third or positive 6
2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4
(c + 3)(c^2 - 3c + 9)
3c-25=17-c 3c+c=25+17 4c=42 c=10.5
c = 4, c squared = 16, 3c squared = 48, 48 + 9 = 57.
No, 3c ( c ) = 4c
If you mean 3c = 214, then c = 68
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
3c
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)