Q: If nine fair coins are tossed what is the probability of obtaining at least one head and at least one tail using the complement formula?

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The probability is 3/4.

A single fair die has the numbers 1 to 6, so when a single fair die is tossed the probability of obtaining a number different than 11 is: P(x diff than11) = 1.

Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.

The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.

assuming we are talking about standard dice here (six sided, numbered 1-6) then the probability of obtaining a result other than 12 when a single die is tossed is 100%. There is no way to roll a 12 after 1 toss of 1 die, therefore the chance of getting anything other than 12 is guaranteed

Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.

The probability is 1/16.

1/4 if they are tossed only once.

The probability is 50-50.

Coins do not have numbers, there is only the probability of heads or tails.

The probability is 1/4

50%

75%

It is 0.5

The probability is 3/8 = 0.375

0

It is 3/4

50/50

It is 0.25

The probability of tossing two heads in two coins is 0.25.

Assuming that it is a fair coin, the probability is 0.9990

The probability is 0.5

The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5

There are 6 outcomes, a 2 is one of them so the probability is 1/6.

50%

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