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Q: If one angle of a rhombus is 90 degrees it must be a square?

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Not only can it, but it must (unless it is a square).

The answer is it must be a rhombus

No, one angle of a square is 90 Degrees. Since there are 4 angles in a square you must multiply the degree of one right angle by 4. Therefore a square actually measures 360 degrees.

A rhombus, or a square if there's a right angle. ( if there's one, there must be 4!)

A rhombus doesn't need any right angles to be a rhombus, although it can have them if it wants to. If a rhombus has right angles, then it's a square. And if it has one right angle, then it must have four of them.

A rhombus must have a pair of opposite angles which are obtuse (and equal).

It must be a rhombus

ms. claudia always told me that a square can be a rhombus but a rhombus cant be a square. another way is a square has 4 90 degree angles but a rhombus has 4 45 degree angles, because all figures must always ALWAYS ALWAYS add up to 360 degrees.

The quadrilateral that must have diagonals that are congruent and perpendicular is the square. This is because its diagonals form a right angle at its center.

A rhombus is a tetragon (or quadrilateral, what ever you want to call it) has two sets of parallel lines, all which are the same length.A square fits the above description, therefore, a square is a rhombus. For a two dimentional object to be square, it must fit the descriptions for the rhombus as well as have 4 right angles.Another contributor conjectures:In order to prove a given rhombus a square, I thinkit's sufficient to show that it has one right angle.

The idea is to show something must be true because when it is a special case of a general principle that is known to be true. So say you know the general principle that the sum of the angles in any triangle is always 180 degrees, and you have a particular triangle in mind, you can then conclude that the sum of the angles in your triangle is 180 degrees. So let's look at one you asked about so you get the idea. The diagonals of a square are also angle bisectors. Since we know a square is a rhombus with 90 angles, if we prove it for a rhombus in general, we have proved it for a square. Let ABCD be a rhombus. Segment AB is congruent to BC which is congruent to CD which is congruent to DA Reason: Definition of Rhombus Now Segment AC is congruent to itself. Reason Reflexive property So Triangle ADC is congruent to triangle ABC by SSS postulate. Next Angle DAC is congruent to angle BAC by CPCTC And Angle DCA is congruent to angle BCA by the same reason. We used the fact that corresponding parts of congruent triangles are congruent to prove that diagonals bisect the angles of the rhombus which proves it is true for a square. The point being rhombus is a quadrilateral whose four sides are all congruent Of course a square has 4 congruent sides, but also right angles. We don't need the right angle part to prove this, so we used a rhombus. Every square is a rhombus, so if it is true for a rhombus it must be true for a square.

All the angles of a square must be 90 degrees. A pentagon can have angles of any size except that, since they must sum to 540 degrees, one of them, at least must be greater than 90 degrees.

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