104
47
I'm having some trouble understanding exactly what 'm' and 'x' have to do with the rectangle. A look at the drawing would really help.
Points S and V
i think 2
There is no simple way. A polynomial of the form f(x) = ax4 + bx3 + cx2 + dx + e may have four real factors: it may have none. Binomial factors will be of the form px + q, where p is one of the factors of a and q is one of the factors of e. In general, p and q can be positive or negative. That gives a very large number of possible binomial factors of the polynomial. Evaluate f(x) for x = -q/p, that is, substitute x = -q/p in the polynomial and calculate its value. If f(-q/p) = 0 then (x + q/p) = (px + q) is a factor. It may be possible to find the zeros of the quadratic by numerical or graphical methods. If x = z if a root then (x + z) is a factor. If the four factors are (x - s), (x - t), (x - u) and (x - v) then s+t+u+v = b/a st +su+ sv + tu + tv +uv = c/a stu + stv + suv + tuv = d/a and stuv = e/a One option is to solve these equations simultaneously for s, t, u and v.