996
997
998
999
There are no two consecutive whole numbers that sum to 142.With two consecutive whole numbers, one is even and the other odd, and their sum will be odd, but 142 is even.Two consecutive even numbers that sum to 142 are 70 and 72.
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
the sum of first 50 consecutive odd numbers is 9801
two consecutive 4- digit numbers have a sum of 9173.what are the numbers?
There are four consecutive 3-digit numbers with a sum of 2,494: 622, 623, 624 and 625.
You can solve this problem algebraically: (X) + (X+1) + (X+2) + (X+3) = 3990 4X + 6 = 3990 4X + 6 - 6 = 3990 - 6 4X = 3984 4X/4 = 3984/4 X = 996 Therefore, the 4 numbers are 996, 997, 998, 999 996 + 997 + 998 + 999 = 3990
They are: 4586+4587 = 9173
-863
There are no two consecutive whole numbers that sum to 142.With two consecutive whole numbers, one is even and the other odd, and their sum will be odd, but 142 is even.Two consecutive even numbers that sum to 142 are 70 and 72.
No
No two consecutive integers have a sum of 2012.
The two consecutive numbers that have a digit sum of 27 and 1 are 999 and 1000. explanation: 9+9+9= 27 1+0+0= 1 (does not matter how many zeros you add, it will always equal 1) Next number after 999 is 1000.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 60 consecutive odd numbers is 3,600.
the sum of first 50 consecutive odd numbers is 9801