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If the area of the square is increased by 69 percent how much the length of the side will increase?
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∙ 11y ago
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Wiki User
∙ 11y ago
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If the side of a square is doubled in size to 8 by what percent did its area increase?
If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.If the side of a square doubles, its area increases by a factor of 4 - an increase of 300%.
A rectangular garden has a width of 5 feet and a length of 10 feet If an equal amount is added to both the width and the length the area is increased to 84 square feet What is this amount?
2
What is the area of a square with sides the length of six?
The area of a square of length m is m2 Accordingly, for a square of side length 6 length units = 62 square units. = 36 square units
What is the formula for the length of a square?
The length of a square is not determined by a formula, it is determined by measuring the square.
How do you work out the length and width of a square?
The length and width of a square are equal. Thus, find the square root of the area and the answer = length= width.
If the length of each side of the square is increased by 10 percent by what percent does the area of the square increased?
10
If the sides of a square are increased by twenty percent by what percent does the area of the square increase?
By 44%. Here is how you calculate it: 20% increase is equivalent to an increase by a factor of 1.2 (100% + 20%, converted to decimal). Square that, and you get 1.44 (44% more than the original).
How many times is the period of the pendulum increased or decreased when its length is increased four times?
Time period is directly proportional to the square root of the length So as we increase the length four times then period would increase by ./4 times ie 2 times.
Is the length of a side of a square and its area nonlinear?
I assume you mean the relationship between the length and the area. Indeed, it is non-linear. The increase in area is proportional to the square of the length of the side. For example, if the length of the side is increased by a factor of 10, the area is NOT increased by a factor of 10, but by a factor of 100.
How many square centimeters does the area increase if the length and width of a rectangle with a perimeter of 62 are each increased by 2 centimeters how do you solve this?
66
How much percent of the side should be increased so that the area of the square should increase 800 percent?
200%. Careful here! An 800% increase is equivalent to multiplying by 9 - NOT 8. So the sides need to be multiplied by sqrt(9) = 3. That is an increase of 200%
If kinetic energy is increased by 60 percent then momentum will be?
Kinetic energy is proportional to the square of the speed; use this fact to calculate the increase in speed (60% increase means an increase by a factor of 1.6). Momentum is proportional to the speed.
When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
If the area is increased by 69 then how much the side of the square will increase?
Each side will increase by the square root of 69 (approx. 8.3).
If the surface area of a sphere is increased by a factor of 4 what is the change in the length of the radius of the sphere?
The area of a sphere is A=4*3.14 * r^2. Thus the area varies as the square of the radius. If the surface area is increased by a factor of 4, then the radius will have to increase by the square root of 4 which is 2.
Suppose the length and width of rectangle is 40 percent more is area also 40 percent more?
No. The change of the area is the square of the change of the length and width.If the length and width are 40% more, they got multiplied by 1.4 .So the area got multiplied by (1.4)2 = 1.96 . That's an increase of 96% .
When an error of 1 percent is made in the length of a square error is?
The error in its area is then 2 percent....
