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Integers are x, x + 2 and x + 4.

2x + 4 = 5x + 10 - 51

3x = 45 so x = 15 and the other integers are 17 and 19.

Check: 15 + 19 = 34, 5 x 17 = 85, 85 - 51 = 34. There you have it.

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Q: If the first and third of three consecutive odd integers are added the result is 51 less than 5 times the second integer Find the third integer?
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If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.


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First, an equation is needed. We will designate the first integer as N, and the second as N + 2. The sum of the two numbers is 176, so the equation should look like this:N + N + 2 = 176Now it needs to be added:2N + 2 = 176Now both sides need to be subtracted by 2:2N = 174Now both sides need to be divided by 2:N = 87Therefore, the first integer is 87. Since the second integer is designated by N + 2, and N is equal to 87, the second integer is 87 plus 2, which is equal to 89.So the two consecutive odd integers whose sum is 176, are 87 and 89.

Related questions

What is the second integer if three consecutive integers have the sum of 153?

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FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?

If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.


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