The Area of a square can be written as it's side length^2, or
A = s^2
if the side length is doubled, then s' is 2s.
A' = (s')^2
A' = (2s)^2
A' = 4s^2 = 4*A
When the side length is doubled, the area increases by a factor of 4
the area should double also Answer 2 The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.
A=L(squared) (for a square only) Lets say our original square is L=2 then area is A=4 so if we double the Area A=8 then l=? L=square root of 8 therefor what ever your area is the Length of each side is the square root of the Area (on the first problem) square root of 4 is 2 therefor L is 2 Makes sence?
Area = Length * Length Area = Length2 Length = Area Length = 230 Length = 15.16575..... -Oliver Crow
The length of a square with an area of 81 would be 9.
The length and width of a square by definition are of equal length. The area (A) of a square = d2, where d is the length of one side. If the area is known, then the length of the side of a square, d = √A (square root of A).
Doubling the length of the sides of a square results in the area being quadrupled (four times the original area).
No, it will be quadrupled.
Area = length*width new Area = 2 * length * width Area is doubled
if length is doubled then resistivity increases&when area is doubled resistivity decreases.
If a square has a side length of 4 centimetres, then its area is equal to 4 x 4 = 16cm2 (16 square centimetres).If a square has a side length of 8 centimetres, then its area is equal to 8 x 8 = 64cm2 (64 square centimetres).Therefore, by doubling the side length of a square, the squares area quadruples.
the new area will be fourfold, not doubled. try it on squared paper and see how the shape increases from one square into four...
the area should double also Answer 2 The area will quadruple. Imagine a square with sides 1 x 1. If you doubled the length of the sides you'd have a square of 2 x 2. You'd be able to get four 1 x 1 squares inside that.
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
If the circumference of a circle is doubled, the area will be four times bigger. It's like having a square with one metre sides. If we double the length of sides, that is - two metre long sides. the length around will be eight instead if four metres. The area will not be doubled from one square metre to two square meters. It will be four square metres instead. Lengths only grow in one direction so doubling is doubling, but areas grow in two directions - length and width at the same time. Therefore, areas grow and grow, doubling this way and doubling that way, so the doubling is doubled making it four times. Trebling would be trebled making a three times length increase into a nine times area increase.
A=L(squared) (for a square only) Lets say our original square is L=2 then area is A=4 so if we double the Area A=8 then l=? L=square root of 8 therefor what ever your area is the Length of each side is the square root of the Area (on the first problem) square root of 4 is 2 therefor L is 2 Makes sence?
if length and width are doubled then the volume should mulitiply by 8
The area also doubles.