the answer is 20
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.
Side length x 6 = perimeter
i think its 288
The diagonals of a rhombus intersect at 90 degrees therefore it has 4 right angle triangles with sides of 5 and 6 respectively with the hypotenuse being a side of the rhombus. So using Pythagoras' theorem: 52+62 = 61 and the square root of this is the length of each side of the rhombus which is approximately 7.81 units of measurement
24 inches
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
Perimeter: 4 times square root of (3.5^2+6^2) = 2 times square root of 193 in cm
Since the diagonals of a rhombus are perpendicular and bisect each other, then we can use the Pythagorean theorem to find the length of the side of the rhombus. So in the right triangle, whose length of the legs are 6 and 8 centimeters, the hypotenuse length (the length of the side of the rhombus) is √(62 + 82) = √(36 + 64) = √100 = 10 cm.
The four sides of a rhombus are equal and so: 6+6+6+6 = 24
30
28
Rhombus is an equilateral four sided form. If one side is 6, the perimeter is 4 x 6 = 24. The altitude makes no difference.
If its base diagonals are 8 and 6 then by using Pythagoras it will have 4 equal lengths of 5 cm. Check: 0.5*8*6*1/3*5 = 40 cubic cm
Side length x 6 = perimeter
i think its 288
Possibly 3 by 6
hexagon has 6 sides. perimeter is addition of the lengths of all sides. 16 x 6 = 96