42/7 = 6 units of length.
133 Let's say the side length equals a Then, the solution is P=7a=7ยท19=133
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
36/6 cm
40
Assuming a regular ten-sided shape, of which every side is the same length, each side will be 114/10 = 11.4 centimetres.
133 Let's say the side length equals a Then, the solution is P=7a=7ยท19=133
784 inches.
12
12
The perimeter of a regular hexagon is (6 x the length of one side).
Yes, a regular heptagon can be constructed as long as there are seven angles measuring 128 and four seventh degrees each. All seven sides must be of equal length.
Perimeter of regular 6 sided hexagon: 6*7 = 42 inches
If the permiter of a regular octagon is 8z-16, then the length of each side would be the perimeter / 8 or 2z-2
Since a pentagon has 5 sides, you divide the perimeter by 5.
Each side is 56/8 (7).
If each side is 1cm long then its perimeter is 8 times 1cm = 8 centimeters
If a pentagon, which is a 5-sided figure, has 26.8 for a perimeter, then each side of that regular pentagon is 26.8 divided by 5 = 5.36 long. How do you get 26.8 for the perimeter of a regular pentagon? Use a regular pentagon with 5.36 for a side length.