Let the number be 'm' & 'n'
Hence
Product ; mn = 80
Sum ; m + n = 21
m = 21 - n
Substitute
(21 - n) n = 80
21n - n^2 = 80
n^2 - 21 n + 80 = 0 It is now in quadratic form to factor.
( n - 16)(n - 5) = 0
Hence the numbers are 5 & 16
16 and 5. 16 + 5 = 21 16 x 5 = 80
Two numbers have a product of 80 their sum is 24?
It is 23 because 17+19+21+23 = 80
80 is.
The product of the two integers is -80.
The answer is -10 and -8. -8 + -10= -18 -8x-10 =80.
Two numbers have a product of 80 their sum is 24?
The numbers are: -10 and -8
23+21+19+17=80
It is 23 because 17+19+21+23 = 80
There's only one number that's equal to 80. It's 80.There's a good chance that there could be three numbers whose sum is 80, or threedifferent numbers whose joint product is 80, but the question doesn't ask for those.
41 & 39 = 1599. (40 x 40 = 1600 but I assume you meant different numbers)
-10 + -8 = -18 -10 x -8 = 80 The two numbers are therefore -10 and -8.
The sum of the first sixteen numbers of pi is 80.
8 + 10 = 188 x 10 = 80Therefore, the two numbers are 8 and ten
-73
Let the two numbers be x and y. According to question, x * y = 80.....................(1) and x + y = 21.................................................(2) (1) implies that y=80/x......................................(3) Now, Substituting this value in equation (2) we get, x + 80/x=21 or x2 - 21x + 80=0. Solving this quadratic equation x=16 and x=5. If x=16, then (3) implies y=5 If x=5, then (3) implies y=16. Hence the two numbers are 16 and 5.
80 as a product of prime numbers can be expressed as: 2x2x2x2x5