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Let the number be 'm' & 'n'

Hence

Product ; mn = 80

Sum ; m + n = 21

m = 21 - n

Substitute

(21 - n) n = 80

21n - n^2 = 80

n^2 - 21 n + 80 = 0 It is now in quadratic form to factor.

( n - 16)(n - 5) = 0

Hence the numbers are 5 & 16

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lenpollock

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4mo ago
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Wiki User

15y ago

16 and 5. 16 + 5 = 21 16 x 5 = 80

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Q: If the product is 80 and the sum us 21 what are the numbers?
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