y=-1x
y = 0. You can get this from the slope-intercept equation of the line.
Slope = 0, intercept = 3
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
y = 5x - 3
It appears to be: y = 2x+3
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
If the slope is 2 and the coordinate is (0, 3) then the equation is y = 2x+3
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
y = 0. You can get this from the slope-intercept equation of the line.
Slope = 0, intercept = 3
The equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is (0, -10), the equation of the line is y = 3x - 10.
y = 5x - 3
The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.
Th estandard slope intercept form is y = mx + b where m = slope of line and b = y intercept when x = 0 For a horizontal line m = slope = 0 equation for horizontal line is y = b
It appears to be: y = 2x+3
The equation of: y = 5x-3 would satisfy the given conditions.