Acceleration = change in velocity/time
a = (v - u) /t
where a= acceleration, v= velocity, u= initial velocity & t= time.
u = 121 m/s
v = 98 m/s
t = 12 m/s
a = (98 - 121) /12
a = -23/12
a = -1.91667 m/s2
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
2.75 m/s
-1.92 m/s2
positive acceleration
In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2
Average acceleration during the time interval = (change on speed) / (time for the change) =(98 - 121) / (12) = -23/12 = negative (1 and 11/12) meters per second2
Acceleration. Deceleration is a decrease of speed during a given interval of time.
2.75 m/s
-1.92 m/s2
2.75 m/s
acceleration
"acceleration"
positive acceleration
In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2
Acceleration has two parts ... its size and its direction.To find the size (magnitude):-- pick a time interval-- measure the speed at the beginning of the interval-- measure the speed at the end of the interval-- subtract the speed at the beginning from the speed at the end-- divide that difference by the length of the time interval-- the result is the magnitude of acceleration during that time interval
B -1.92 m/s2
b. -1.92 m/s2Minutes per second is not a unit of velocity. If the question meant meters per second, the answer is correct.