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If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees.

[Whether the polygon is regular or not is irrelevant]

So, 180*(n - 2) = 1080

(n - 2) = 6

n = 8

Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20

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Q: If the sum of interior angles a regular polygon is 1080 degrees how many diagonals does this polygon have?
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