n = (3240 + 360)/180 ie 20
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
Sum of the angles of a regular polygon = (#sides - 2) * 180. Sum of 20-gon angles = (20-2) * 180 = 3240
3240. Stick it to Iqity.
The GCF is 72.
3240 = 23 x 34 x 51
20 sides
18 Angles on a straight line = 180 degrees interior angles 2880 + exterior angles 360 = 3240 degrees 3240 divided by 180 = 18 sides Note that the exterior sum of angles of any polygon is always 360 degrees.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 3240 degrees
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.
A "polygon angles sides" makes no sense. So it is not clear what is 3240. Second, the question does not say the what is to be summed. Please resubmit after thinking a bit more about the question.
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
The interior angles of a 20 sided polygon add up to 3240 degrees
20
The interior angles add up to 3240 degrees
The interior angles of a 20 sided polygon add up to 3240 degrees
20 sides The relationship between the sum of interior angles and number of sides is (Sum of angles)/180° + 2 3240/180 + 2 = 18 + 2 = 20 This kind of figure is called an icosagon. 20 sides Alternatively you can find it from the formula Sum of the angles of an n-sided polygon = 180(n-2). So solve the following for n: 3240= 180(n-2) n-2=3240/180=18 n=18+2=20