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If two fair dice are rolled what is the probability of rolling a double given that the sum was 11?
Wiki User
∙ 15y ago
Let A = rolling a double Let B = sum is 11 P(A)=6/36=1/6 P(B)=2/36=1/18 since (5,6) and (6,5) produce a sum of 11. We want to find P(A/B)= P(A & B) / P(B) = 0 / P(B)=0 P(A & B) represent the event getting a double and the sum being 11.
Wiki User
∙ 15y ago
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What is the probability of rolling a given number on a die?
On a regular number cube, it is 1/6.
A coin is tossed and then a die is rolled Find the probability of getting a 5 on the die given that the coin landed tails up?
9/2
If a coin is tossed and then a dice is rolled what is the probability of getting a 5 on the dice given that the coin landed tails up?
These are independent one has no bearing on the other
What is the probability of rolling a 4 on a number cube and flipping tails on a coin?
The probability of rolling any number on a cube can be represented by the formula: X / the number of variables. Since any cube has 6 sides, the probability of rolling any of the numbers 1 through 6 on the cube, can be represented by the formula: X = 1 / 6 = 16.66% The odds or probability of flipping a coin and landing it on either side can be represented by X = the requested result / the number of variables = 1 /2 = 50% Therefore, given the two questions of probability, there is a much greater chance of landing a coin on "tails" rather than rolling a "4".
What is the probability of rolling a number greater than or equal to 8 with two dice given that at least one of the dice must show a 6?
5/36
If a die is rolled 375 times and 5 occurs 80 times what is the probability of rolling a 5?
The probability of rolling a 5, based on the information given, is 80/375 or 16/75. Your problem describes a relative frequency approximation of probability.
What is the probability of getting 5 in rolling a die given that 6 has occurred already?
If it is a fair die and rolled fairly, the two events are independent so that the probability is 1/6.
After a die has been rolled shouldn't the probability be 50 50 for any given outcome it either is or it isn't so it is a certain number should have the probability 1 2 More semantics than math?
Assuming as the die is rolled, and its a 6-sided die (1, 2, 3, 4, 5, & 6), each number has a 1/6 probability of being rolled. The probability of any number being rolled is 1/6 and the probability of not rolling that number is 5/6. Something that has only 2 outcomes, such as boy & girl or heads & tails, will have the 50 50 probability.
What is the probability of rolling a given number on a die?
On a regular number cube, it is 1/6.
What is the probability of rolling a five with a pair of dice?
There are 36 possible outcomes when we roll a pair of dice. Rolling a five can be done the following ways: 3-2, 4-1, 2-3 and 1-4. That's four ways to roll a five with one roll of the dice. The odds of rolling a five are 4 in 36, or 1 in 9. That makes the probability of rolling a five equal to 0.11111....We know that the probability of something is a ratio of the number of times it can be done to the total number of things that are possible. Probabilities range from zero to one, inclusive. If something has a probability of zero, it cannot happen. Like rolling a 13. A 13 cannot be rolled with one roll of a pair of standard dice. Thus the probability of rolling a 13 is zero, as it cannot happen.If something has a probability of one, it must happen. Like the probability of rolling an odd or an even number with one roll of a pair of dice. Since any number we roll must be either odd or even, then the probability of rolling an odd or an even number with one roll of a pair of dice is one. An odd or an even number must turn up, and that is why the probability of rolling an odd or an even number with one roll of the dice is one. Lastly, we've seen that the probability of rolling a given number with one roll of the dice is the number of times that number might appear divided by the total number of possibilities that might appear.
How do you figure out the probability of 2 separate events For instance what is the probability of flipping a coin to heads and rolling a 5 on a dice?
You take the probability of each event and multiply them. In the case of the given example, your odds or flipping a head and rolling a 5 would be 1/2 * 1/6, which equals 1/12.
A coin is tossed and then a die is rolled Find the probability of getting a 5 on the die given that the coin landed tails up?
9/2
If a coin is tossed and then a dice is rolled what is the probability of getting a 5 on the dice given that the coin landed tails up?
These are independent one has no bearing on the other
What is the probability of obtaining tails and a three?
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
What is the probability of rolling a 4 on a number cube and flipping tails on a coin?
The probability of rolling any number on a cube can be represented by the formula: X / the number of variables. Since any cube has 6 sides, the probability of rolling any of the numbers 1 through 6 on the cube, can be represented by the formula: X = 1 / 6 = 16.66% The odds or probability of flipping a coin and landing it on either side can be represented by X = the requested result / the number of variables = 1 /2 = 50% Therefore, given the two questions of probability, there is a much greater chance of landing a coin on "tails" rather than rolling a "4".
You roll two number cubes what is the probability that you roll a 1 first and a 2 second?
Since there are 6 sides on every die that are equally likely to be rolled, the probability of rolling any given side once is exactly 1/6. The 2 events or the first and second dice roll are independent (the outcome of one does not influence the other) so to find the probability of both occurring you just multiply the probability of each event. Since each event has a 1/6 probability of occurring as stated before, The entire event has a probability of 1/6*1/6 or 1/36, which is approximately 2.78%.
What is the probability of rolling a number greater than or equal to 8 with two dice given that at least one of the dice must show a 6?
5/36
