Best Answer

x +y = 64

x divided by Y = 7 So what times seven equals a number close to 64

7x2 = 14

7x3 = 21

7x4 = 28

7 x5 = 35

7x6 = 42

7x7= 49

7x8 = 56 64 - 56 = 8

therefore x = 56 and y = 8 and to prove correct

56 + 8 = 64

56 divided by 8 = 7

Q: If two numbers have a sum of 64 and the quotient is 7 what are the two numbers?

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