x +y = 64
x divided by Y = 7 So what times seven equals a number close to 64
7x2 = 14
7x3 = 21
7x4 = 28
7 x5 = 35
7x6 = 42
7x7= 49
7x8 = 56 64 - 56 = 8
therefore x = 56 and y = 8 and to prove correct
56 + 8 = 64
56 divided by 8 = 7
64 & 8
The two numbers that have a product of 64 and a sum of 16 are 8 and 8. Since both numbers are the same, their product is (8 \times 8 = 64) and their sum is (8 + 8 = 16).
The sum of the prime numbers 11 and 53 equals 64.
The numbers are 32.5 and 31.5
61 and 3
64 & 8
The numbers are 98 and 64
The two numbers that have a product of 64 and a sum of 16 are 8 and 8. Since both numbers are the same, their product is (8 \times 8 = 64) and their sum is (8 + 8 = 16).
The sum of the prime numbers 11 and 53 equals 64.
29 & 35
The numbers are 32.5 and 31.5
There are two consecutive even numbers. The numbers are 62 and 64.
61 and 3
64
They are 36 and 64
They are 36 and 64
64 and 65