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Let the width be (x-2) and the length be x:

width*length = area

(x-2)*x = 35 square inches

x2-2x = 35

x2-2x-35 = 0

Solving the above quadratic equation works out as:

x = -5 or x = 7 it must be the latter because dimensions can't be negative

Therefore: length = 7 inches and width = 5 inches

Check: 7*5 = 35 square inches

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โˆ™ 2010-06-17 15:22:27
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Q: If width of a rectengle is 2 inches less than its length and the area is 35 square inches what are the length and the width of the rectangle?
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