That depends on the angle of elevation
If the reference point and an object are both on the horizon then the angular distance to the object, relative to the reference point is simply the angle formed between the two rays from the observer to object and to the reference point. If either the object or reference point (or both) are not in the plane of the horizon then the appropriate rays are the projections of the rays from the observer onto the plane containing the horizon.
Aircraft fly in the direction of their destination regardless which way around the world that may be. That's a trick question. To an observer standing at the North Pole, a plane flying east to west is going clockwise. To an observer standing at the South Pole, a plane flying west to east is going clockwise. And, of course, some planes fly over the poles. But if you only consider planes that are flying east/west, they are going both clockwise and counterclockwise, depending on which direction you are viewing them from.
because they are parallel to the plane of the horizon
The answer depends on how fast the plane is flying.
linear motion
If the reference point and an object are both on the horizon then the angular distance to the object, relative to the reference point is simply the angle formed between the two rays from the observer to object and to the reference point. If either the object or reference point (or both) are not in the plane of the horizon then the appropriate rays are the projections of the rays from the observer onto the plane containing the horizon.
This is an ambiguous question. There are too many variables: pitch angle, fuel level, rate of descend/climb, trim, airspeed of plane, wind direction and speed....... ----------------------- That's a trig question (it's not ambiguous:RTFQ) Do your own homework ! -----------------------
The zenith is the direction directly above the observer. The astronomical horizon is the plane that is perpendicular to that direction, i.e. horizontal. The "true horizon", however, is the cone from the observer to the point on the earth, below which you can not "see over", so it is a small amount lower in angle. In practice, the two horizons can be considered to be the same, because the height of the observer is often small in comparision to the diameter of the earth, unless the observer is standing on a tall point, such as a mountain.
Zero. I am currently sitting in my chair in my room. If the plane is my chair and my room is the reference plane as long as I don't move my chair around the room it has no kinetic energy. Now if I expand my reference plane to an observer on the sun (I know) they are going to see me and my chair hauling butt at about 30km/s around the solar system along with my room my house and the rest of the planet this velocity and my mass mean there is kinetic energy. Ek=.5mv^2
Aircraft fly in the direction of their destination regardless which way around the world that may be. That's a trick question. To an observer standing at the North Pole, a plane flying east to west is going clockwise. To an observer standing at the South Pole, a plane flying west to east is going clockwise. And, of course, some planes fly over the poles. But if you only consider planes that are flying east/west, they are going both clockwise and counterclockwise, depending on which direction you are viewing them from.
The horizon runs horizontal. Perpendicular to that is VERTICAL.
Flying in a plane has always been open to the public.
There is not a map for flying on the plane
No plane has trouble flying in the rain.Only the smallest like cessna may have trouble flying in the rain.
The height of the plane is quite insignificant, compared to the altitude at which it flies. In old times, the altitude couldn't be measured with such precision. Nowadays, with GPS, it might refer to wherever the GPS device is located - but it doesn't really make much difference.
The sight line to the point where the aircraft touches the horizon is a tangent to the surface of the earth. This forms the second leg of a right angled triangle with the radius of the earth as the other leg and the radius of the earth plus the height of the plane above the surface of the earth as the hypotenuse. There are two assumptions that are going to have to be made about the observation made of the aircraft, both of which will make small adjustments to the real distance, but with the accuracy of the figures used, they will be insignificant: 1) The assumption that the earth is spherical; it isn't, it's geoid shaped - a sphere flattened at the poles and bulging around the equator; 2) The observer is looking along the surface of the earth (most likely out to sea) at mean sea level and not some 5-6 ft above it A third assumption is that the aircraft is flying parallel to the curvature of the earth at a steady altitude of 36,000 ft above mean sea level (known as horizontal flight). The radius of the earth is about 3959 miles. 36000 ft = 36000 ÷ 5280 miles ≈ 6.8 miles The distance to the aircraft can then be calculated using Pythagoras: distance_to_aircraft ≈ √(3965.8² - 3959²) ≈ 232 miles. Along the surface of the earth (to the point directly under the aircraft) it is slightly less, but still approx 232 miles. (it can be calculated by 3959 × arccos(3959/3965.8) with the inverse cosine calculated in radians not degrees.)
how do you star flying a plane in aces high 2 ? how do you star flying a plane in aces high 2 ?