Could be a trick question:
1 light year = 6 trillion miles, which is a 13-digit number......13 seconds.
Or, the question could be interpreted as counting to 6 trillion at a rate of 1 number/sec. In this case, about 1900 centuries.
-3
9.
Counting in hexadecimal is basically like counting in decimal - just remember that the highest digit is "F" instead of "9". So, after "9", you continue with the digits "A", "B", ... "F", and after the last digit gets to "F", you set it back to zero (just as in decimal, you would set the last digit to zero after a "9"), and add one to the previous digit. For example, the next number after 3F is 40. And the next number after 3FF is 400.
No
All of the whole numbers from 10 to 99.
-3
one
99
It is: 10
9.
4 significant figures (because this number has a decimal, start counting at the first non-zero digit from the left...so count 2300).
Counting in hexadecimal is basically like counting in decimal - just remember that the highest digit is "F" instead of "9". So, after "9", you continue with the digits "A", "B", ... "F", and after the last digit gets to "F", you set it back to zero (just as in decimal, you would set the last digit to zero after a "9"), and add one to the previous digit. For example, the next number after 3F is 40. And the next number after 3FF is 400.
If your asking in a digit it's called a 4 digit number and it is the smallest 4 digit number
There's no such thing as one consecutive digit. There has to be at least two of them.When you count, consecutive digits are numbers that you name in a row, with nothing else between them.Examples:34 and 35 are consecutive. There's no counting number between them.97 and 98 are consecutive. There's no counting number between them.62 and 64 are not consecutive, because 63 comes between them.
No
The digit with the second greatest value in the number is '1'. its value is second to the largest number which is 2.
All of the whole numbers from 10 to 99.