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Answered 2010-11-06 22:21:44

Could be a trick question:

1 light year = 6 trillion miles, which is a 13-digit number......13 seconds.

Or, the question could be interpreted as counting to 6 trillion at a rate of 1 number/sec. In this case, about 1900 centuries.

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How many three digit number contain the digit 2?

There are several ways to answer this. I think this is the easiest: Count the number of three-digit numbers: The first digit can be 1-9; the second and third digits can be 0-9. So, there are 9 choices for the first digit and 10 choices for the second and third digits. This gives you 9 x 10 x 10 = 900 three-digit numbers. Right? Then count the number of three-digit numbers that do NOT contain the digit 2. This is done similarly! Try it! Now, if you think about it, the difference between these two quantities IS the number of three-digit numbers that DO contain a 2, which is what you wanted.

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How does hexadecimal count?

Counting in hexadecimal is basically like counting in decimal - just remember that the highest digit is "F" instead of "9". So, after "9", you continue with the digits "A", "B", ... "F", and after the last digit gets to "F", you set it back to zero (just as in decimal, you would set the last digit to zero after a "9"), and add one to the previous digit. For example, the next number after 3F is 40. And the next number after 3FF is 400.

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How many three digit numbers can be made out of all the numbers from 1 to 9 with out repeating any number?

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Assuming you mean whole numbers and leading zeros do not count, the smallest 3 digit number is 100.

Can counting number a decimal?

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a number between 25 and 35 whose digits make a product of 16Answer:If I understand your question, the last digit in counting is nine (9) and the first is zero (0). When counting objects it starts; none (or zero), 1, 2, . . . 9

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How do you open the safe in crisis core?

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Guessing 10 000. The zeros count as a digit. The greatest possible is 99 999. =)

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