Set up your equations based upon the following: Let N = number of nickles. Let N + 1 = number of dimes. Let 5N = the value (in cents) of all the nickles. Let 10(N + 1) = the value (in cents) of all the dimes. Let 235 = the total value (in cents) of all the coins (nickles and dimes). In English, the value of the dimes plus the value of the nickles equals the total value of the coins. Algebraically, we write: 5N + 10(N + 1) = 235 The distributive law of multiplication lets us rewrite that this way: 5N + 10N + 10 = 235 Grouping lets us write that this way: 15N + 10 = 235 Subtracting 10 from both sides of the equation yields: 15N = 225 Dividing both sides by 15 yields: N = 15 So, we have 15 nickles and 15 + 1, or 16, dimes.
10.9
If there are 150 nickles and dimes and 70 more are nickles than dimes how many of each are there?
40 Dimes and 8 Nickles
Ten dimes, fifteen nickels
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
Since each dime is equivalent to two nickels, you need 80 nickels.
A dime is 10 cents and a nickel is 5 cents, so each dime is the same as 2 nickels. That means 49 dimes are equivalent to 49*2 = 98 nickels.
13 nickels and 78 dime
8 dimes, 1 nickel 7 dimes, 3 nickels 6 dimes, 5 nickels 5 dimes, 7 nickels 4 dimes, 9 nickels 3 dimes, 11 nickels 2 dimes, 13 nickels 1 dime, 15 nickels 17 nickels
7 nickels, 4 dimes, 3 quarters
2 quarters 1 fifty cent piece 1 quarter 2 dimes and a nickel 1 quarter 1 dime and 3 nickels 1 quarter and 5 nickels 5 dimes 4 dimes and 2 nickels 3 dimes and 4 nickels 2 dimes and 6 nickels 1 dime and 8 nickels 10 nickels
7 nickels, 4 dimes, and 3 quarters.
65 pennies 0 dimes and 13 nickels 1 dime and 10 nickels 2 dimes and 9 nickels 3 dimes and 7 nickels 4 dimes and 5 nickels 5 dimes and 3 nickels 6 dimes and 1 nickel 2 quarters and 1 dime and 1 nickel That's all I can think of, but there are much more!
If there are 150 nickles and dimes and 70 more are nickles than dimes how many of each are there?
9 ways: 2 dimes, 0 nickels, 1 penny. 1 dime, 2 nickels, 1 penny. 1 dime, 1 nickel, 6 pennies. 1 dime, 0 nickels, 11 pennies. 0 dimes, 4 nickels, 1 penny. 0 dimes, 3 nickels, 6 pennies 0 dimes, 2 nickels, 11 pennies. 0 dimes, 1 nickel, 16 pennies. 0 dimes, 0 nickels, 21 pennies.
two dimes and two penniesone dime, two nickels, and two pennies
25 pennies 5 nickels 2 dimes and 5 pennies 2 dimes and a nickel a quarter 3 nickels and a dime 10 pennies and 3 dimes 15 pennies and a dime 4 nickels and 5 pennies