Assuming: an 8 inch inside diameter, 1 gallon of water weighs 8.345404 pounds, 231 cubic inches of water to the gallon, volume of cylinder = Pi * radius^2 * height volume=3.14 * 4^2 * (4000 * 12) volume = 3.14 * 16 * 48,000 = 2,411,520 cubic inches 2,411,520 cubic inches of water when full. -------------------------------------------------------------------------- A 4000 foot cylinder/pipe with an 8 inch inside diameter, if full of water, will contain 10,439.48 gallons of water weighing a total of 87,121.68 pounds or 43.56 tons.
261.66
Regression :The average Linear or Non linear relationship between Variables.
Roughly 317.5 feet squared.
This pipe can hold up to 0.5 cubic foot or 3.7 gallons of water.
we will need a full statement of problem.
There are 935.8 cubic feet in a 7,000-gallon tank.
261.66
Regression :The average Linear or Non linear relationship between Variables.
Roughly 317.5 feet squared.
1 acre is approx 4000 sq m8 ft is about 2.4 m.so 1 acre at 8 ft depth = 4000* 2.4= 9600 cu meter===========================1 acre = 43,560 square feetVolume = 43,560 x 8 = 348,480 cubic feet = 9,867.9 cubic meters (rounded)Note: That's the volume of 1 acre 8 feet deep, whether it's empty, or full of sand,mud, water, or old newspapers.
800 cubic feet of water weights roughly 49,941.52 (water volume times density.)
4000
linear integrated circuit
(20' x 12' x 4') = 960 cubic feet
They are each a linear or nearly linear alignment of sun moon and earth.
They are each a linear or nearly linear alignment of sun moon and earth.
15 feet * 30 feet * 8 feet = 3600 cubic feet 3600 * 0.75 = 2700 cubic feet of water 2700 cubic feet = approximately 20,197.4026 US gallons