it's 36.
Only use 50c or $1 or $2, 3 ways
only use 50c and $1, 9 ways,
only use 50c and $2, 4 ways,
only use $1 and $2, 4 ways.
use 50c, $1 and $2, 16 ways.
total is $36
There are 35 ways.
600 dollar
20 5 cents coins
5*20 cents (Australian) make a dollar. In US and Canadian coins, a 50 cent piece, a quarter, two dimes, and a nickel also make a dollar.
Two quarter dollar coins (25 cents each) and five dimes (10 cent each coin) or 3 x 25 cents = 75 cents 3 x 5 cents = 15 cents 1 x 10 cents = 10 cents Total = 100 cents or one dollar.
10- 1 cent 14 - 5 cents 2- 10 cents
600 dollar
20 5 cents coins
100 cents = 1 dollar 5 x 20 cents = 1 dollar 5 x 13 = 65 Answer: there are 65 of 20 cents in $13
10 dimes make one dollar.
I don't think that this can be done using current US coins. In Canada, however, there are at least three combinations: -- 80 cents, 17 dimes, 2 quarters and a two-dollar coin -- 85 cents, 9 dimes, 5 quarters and a two-dollar coin -- 90 cents 1 dime, 8 quarters and a two dollar coin
To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)
5*20 cents (Australian) make a dollar. In US and Canadian coins, a 50 cent piece, a quarter, two dimes, and a nickel also make a dollar.
5 of 10 Cents = $0.50 1 of 50 Cents = $0.50 6 total = $1.00
Two quarter dollar coins (25 cents each) and five dimes (10 cent each coin) or 3 x 25 cents = 75 cents 3 x 5 cents = 15 cents 1 x 10 cents = 10 cents Total = 100 cents or one dollar.
One half dollar, two nickels, two cents.
Yes you you can have: 10 one cents 2 quarters 4 five cents 2 ten cents
A nickel is 5 cents and a dollar is 100 cents, so you need 100/5 = 20 coins.