That's going to depend on the substance,
which the question neglects to identify.
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The volume of any gas at STP (pressure of 1 ATM & temp.: 0oC) is approximately 22.41 L/mol or 22,410 mL/mol. So you need to find out how much gas you have to begin with (# of moles) to find the volume of the gas at STP.
30 degrees Celsius = 303,15 K752 mmHg = 0,9894737 atmosphere
0.0710 mol
The answer is about 30.9 kJ/mol
0.52 mol.
Use the ideal gas law. PV=nRT where P=Pressure, V=Volume, n=amount (mol), R is the constant (since you have mmHg it would be 62.4) and T=temperature (convert to Kelvin). the eqation for density is mass over volume, so use the ideal gas law to solve for volume. Then calculate mass over volume.
A fixed quantity of gas at a constant pressure exhibits a temperature of 27 degrees Celsius and occupies a volume of 10.0 L. Use Charles's law to calculate: the temperature of the gas in degrees Celsius in atmospheres if the volume is increased to 16.0 L
The volume is 0,446 L.
30 degrees Celsius = 303,15 K752 mmHg = 0,9894737 atmosphere
47 degrees Celsius
747 mmHg
by grabing a gun and shooting yourself in the private parts
0.0710 mol
You can't. Celsius per mmHg is a relationship of temperature to pressure. You can however solve for temperature if you have the value of pressure (e.g. if P= 10 mmHg and V/P = 2 ºC/mmHgthen V= (2 ºC/mmHg)(10 mmHg) = 20 ºC). If you have more information in the problem you might be referring to Gay-Lussac's Law, which compares two values of pressure and temperature to show the relationship (GL'sL: P1/T1 = P2/T2 ... but that would be pressure per unit volume). I'm not sure what you are looking for exactly, but you can't convert temp. to pressure (just like you can't convert feet to lbs.).
The answer is about 30.9 kJ/mol
PV=nRT (pressure*volume=mols*value for R*temperature in degrees kelvin) R Values vary, but must match the unit for pressure---> .0821 ATM 62.4 mmHg 8.314kPa temperature must always be in degrees kelvin ( kelvin= degrees celsius+273)
Yes it does. And STP also stands for 760 torr and 1.0 ATM and 273 K.
757.2 mmHg is almost atmospheric pressure (P = 760 mmHg) and therefore the vapour pressure is very close to the normal boiling point.According to the boiling temperature is T = 353.14 K = 79.99 °C at P = 757.2 mmHg.