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If you randomly take a positive integer and divide it by 23 what is the probability that the remainder is 13?
Wiki User
∙ 13y ago
Out of every 23 consecutive positive integers, one of them is evenly divisible by 23, one produces
a remainder of 1, one produces a remainder of 2, . . . . . , one produces a remainder of 13, . . . . . ,
and one produces a remainder of 22.
So the probability that a random integer will produce a remainder of 13 is (1/23) = about 4.35% (rounded)
Wiki User
∙ 13y ago
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