There are six sides on the die, and two of them are less than three. So when you throw the die, there are two possibilities out of six total possibilities that the die will land on either one or two - this means it should happen about 2/6ths, or 1/3rd of the time. Since you're throwing the die 54 times, all that's left to figure out is what 1/3rd of 54 is: 54*(1/3) = 18 So, it should land on a number less than three about 18 times.
40 times
about 18...hope this helps(:
27 - if it was a fair die.
He should expect it 100 times.
The expected number of times is the probability x number of throws. Since you have a prob of 1/6 for a seven, then (1/6) * 160 = 26.67 times you would have success. We generally would round up the expected number of successes to the whole number 27.
I would expect it to land on a number of 4 or higher 50% of the time or roughly 24 times.
40 times
about 18...hope this helps(:
27 - if it was a fair die.
You can expect the spinner to land an odd number 25 times out of 50.
He should expect it 100 times.
12 times.
A fair cube 60 times.
33
Type your answer here... 15
well by 19 tmes
The expected value is 20 times.