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Yes you can.

All you need to know is it's maximum height to find the total time.

We are not concerned with displacement because it's horizontal velocity is constant and there are no horizontal forces.

Let it's maximum height = h

It's vertical velocity at it's highest position = 0

Acceleration due to gravity = g

To find the time it takes the ball to come down from it's highest position can be calculated using the equation, s = ut + (1/2)at2 (Where s= displacement, u= initial velocity, a=acceleration and t=time)

=> h = 0 x t + (1/2)gt2

=> h = (1/2)gt2

=> t2 = 2h/g

=> t = √(2h/g)

The time it takes for the ball to go up is same as it is to come down because the acceleration is same for both the cases, hence the total time the ball remains in air will be 2t = 2 x √(2h/g)

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