All numbers between -11 and 1, excluding -11 and including 1.
36
1000 - 2999 inclusive.2000. It's inclusive, so you must add 1 to the difference.-----------------------------Number of whole numbers = last number - first number + 1The first 4 digit number is 1000The last depends upon whether the "between" is:exclusive: the "between" is "strictly between", ie the numbers under consideration are greater than the first and less than the second; the 3000 is excluded as it is not less than 3000. This is an understanding that comes from placing a third object between two other objects - you cannot place it on top of one of the other objects as it would not be between them;inclusive: the "between" includes the end numbers, ie the numbers under consideration are greater than or equal to the first number and lest than or equal to the second number; the 3000 is included as it is equal to 3000.If exclusive:The last number is 2999 → number of numbers between 999 and 3000 = 2999 - 1000 + 1 = 2000If inclusive:The last number is 3000 → number of numbers between 999 and 3000 = 3000 - 1000 + 1 = 2001--------------------------------------------------------------------------------Numbers are not necessarily whole numbers; four digit numbers also include 999.1, 999.2, ..., 999.9 which mean there could be an extra 9 four digit numbers between 999 and 3000.999.0 wouldn't normally be written with the zero as it makes no different to the value of the number, however if 998.99 was rounded to 4 significant figures the result would be 999.0 with 4 digits, so 999.0 could be claimed to be a four digit number, which would then either be included or not depending upon whether the between is inclusive or exclusive.
3 numbers would be 0.051, 0.052, and 0.053
This would be impossible as, seeing as one of the integers would be odd, the result would be an odd number.
Infinitely many. There are infinitely many numbers between any two numbers. So, for example, cosidering only the numbers that round up, there are an infinitely many numbers between 149.999 and 150, all of which would round to 150. And there are another infinity between 149.5 and 149.999 which, to the nearest unit would round to 150. If you are rounding to the nearest 10, all the numbers between 145 and 150 would also round to 150. In all cases you must also consider the numbers that are rounded down to 150.
WHOLE NUMBERS...The numbers (integers or whole numbers) between two numbers would not include the two numbers, so 9999 - 2 = 9997. Subtract 2 for the numbers 0001 and 9999.Another AnswerThe answer is infinity. If you ask unqualified questions, expect infinite answers.
If you meant to ask what are the prime numbers between 21 and 53 inclusive, then it would be 23, 29, 31, 37, 41, 43, 47, 53
1000 - 2999 inclusive.2000. It's inclusive, so you must add 1 to the difference.-----------------------------Number of whole numbers = last number - first number + 1The first 4 digit number is 1000The last depends upon whether the "between" is:exclusive: the "between" is "strictly between", ie the numbers under consideration are greater than the first and less than the second; the 3000 is excluded as it is not less than 3000. This is an understanding that comes from placing a third object between two other objects - you cannot place it on top of one of the other objects as it would not be between them;inclusive: the "between" includes the end numbers, ie the numbers under consideration are greater than or equal to the first number and lest than or equal to the second number; the 3000 is included as it is equal to 3000.If exclusive:The last number is 2999 → number of numbers between 999 and 3000 = 2999 - 1000 + 1 = 2000If inclusive:The last number is 3000 → number of numbers between 999 and 3000 = 3000 - 1000 + 1 = 2001--------------------------------------------------------------------------------Numbers are not necessarily whole numbers; four digit numbers also include 999.1, 999.2, ..., 999.9 which mean there could be an extra 9 four digit numbers between 999 and 3000.999.0 wouldn't normally be written with the zero as it makes no different to the value of the number, however if 998.99 was rounded to 4 significant figures the result would be 999.0 with 4 digits, so 999.0 could be claimed to be a four digit number, which would then either be included or not depending upon whether the between is inclusive or exclusive.
Always look at the next digit. If it's between 0 & 4 inclusive - round the number down. If it's between 5 & 9 inclusive - round up. Take the numbers 10.094 and 10.096. 10.094 would round down - to 10.09... 10.096 would round up to read 10.10
[2,7] the bracket means inclusive but if it said exclusive it would have parenthesis replacing the brackets.
if (length>=10 && length<=20) { // length is between 10 and 20, inclusive... }
If you were asked to round to the nearest 100, any number between 50 and 99 inclusive would round to 100. Also any number between 101 an 149 inclusive would round to 100.
The sum.
If at least one of the numbers is even, the result will be even. Otherwise all the numbers are odd and the result will be odd.
That would be 28 itself, since 28 is a multiple of 7.
length ≥ 10 m and length ≤ 20 m
it is very simple we add the numbers of protons with the numbers of neutrons and the result would be the weight of the ion
In general, unless otherwise specified, you should assume the range to be inclusive of the beginning and ending numbers, 10 & 20 in this example. Since neither of these numbers are multiples (even integer multiples that is) of 10 or 20, they wonβt show up as multiples of interest. Should either the beginning or ending range numbers be numbers satisfying the condition, then they would be included in the list. For example, if you want multiples of 6 between 12 and 20, then 12 would be part of the desired list (along with 18). Hope this helps!