This is missing some information. You mentioned the tens digit twice and didn't mention the ten thousands digit. One possibility is 87184.
Telephone Number? Or do you mean, units, tens, hundreds, thousands, tens of thousand, one hundred thousand and a million?
The digit in the hundred thousands place in the number 3,928,764 is the digit 9.This number is read as: three million, nine hundred twenty-eight thousand, seven hundred sixty-four. As you can see, the part of the number you're asking about is "nine...hundred thousand".Remember, from right to left, it goes: ones place, tens place, hundreds place, thousands place, ten thousands place, hundred thousands place, millions place....
One thousand, eight hundred and seven. The first number is the thousands, the second number is the hundreds, the third number is the tens (since its 0, there are none)
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
So far we're at 1,949,2xx
Telephone Number? Or do you mean, units, tens, hundreds, thousands, tens of thousand, one hundred thousand and a million?
7006
From AAA math:Numbers, such as 495,784, have six digits. Each digit is a different place value.The first digit is called the hundred thousands' place. It tells you how many sets of one hundred thousand are in the number. The number 495,784 has four hundred thousands.The second digit is the ten thousands' place. In this number there are nine ten thousands in addition to the four hundred thousands.The third digit is the one thousands' place which is five in this example. Therefore there are four sets of one hundred thousand, nine sets of ten thousand, and five sets of one thousand in the number 495,784.The fourth digit is called the hundreds' place. It tells how many sets of one hundred are in the number. The number 495,784 has seven hundreds in addition to the thousands.The next digit is the tens' place. This number has are eight tens in addition to the four hundred thousands, nine ten thousands, five thousands and seven hundreds.The last or right digit is the ones' place which is four in this example. Therefore there are four sets of one hundred thousand, nine sets of ten thousand, five sets of one thousand, seven sets of one hundred, eight sets of ten, and four ones in the number 495,784.
The digit 5 is 10 thousands. Count from the right. *The last digit is 9 ones, or 9 units. *The 1 stands for a 10, so 19 is nineteen. *The 7 stands for hundreds, so 719 is seven hundred and nineteen. *the 6 stands for thousands, so 6719 is six thousand, seven hundred 'n' nineteen. *the 5 stands for ten thousands, so 56719 is 56 thousand... *the 4 stands for hundred thousands, so you read 456719 as... Four hundred (and) fifty six thousand, seven hundred (and) nineteen.
The digit in the hundred thousands place in the number 3,928,764 is the digit 9.This number is read as: three million, nine hundred twenty-eight thousand, seven hundred sixty-four. As you can see, the part of the number you're asking about is "nine...hundred thousand".Remember, from right to left, it goes: ones place, tens place, hundreds place, thousands place, ten thousands place, hundred thousands place, millions place....
Seven of them
Divide the numbers into millions, thousands, and hundreds: 7,907,979. The 3 numbers on the right (979) are hundreds, the 3 numbers in the middle are thousands (907), and the number on the left is millions (7). So, it's seven million, nine hundred and seven thousand, nine hundred seventy-nine.
One thousand, eight hundred and seven. The first number is the thousands, the second number is the hundreds, the third number is the tens (since its 0, there are none)
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
608,907
For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.
So far we're at 1,949,2xx