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It's an even number, so it can't be expressed as the sum of two consecutive integers.

You can however do:

three consecutive integers: 41 + 42 + 43

four consecutive integers: 30 + 31 + 32 + 33

nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18.

twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16

Q: In how many ways can the number 126 be espressed as a sum of two or more consecutive integers?

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There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.

There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.

No. The concept of consecutive makes sense for integers but not for fractions. Fractions are infinitely dense. This means that there are infinitely many fractions between any two numbers - including between any two fractions. So, given one fraction, f1, there cannot be a "next" or "consecutive" fraction, f2, because there are an infinite number of fractions between f1 and f2.

Nine of them. All consecutive integers have nine tenths between them.

2 and 3 are the only consecutive prime numbers.

Related questions

There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.

Start with "-3", then add one at a time to get as many consecutive integers as you want.

There are 30 such integers.

There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.

31.how do you solve?

All of them from 45 to 99 ... 55 integers.

Many numbers can be expressed as the sum of two or more consecutive integers. For example, the number 15 can be written as the sum of consecutive integers in three different ways: 15=7+8 15=4+5+6 15=1+2+3+4+5 Look at numbers other than 15 and find out all you can about writing them as sums of consecutive whole numbers.

Defining "consecutive" as "following continuously in unbroken or logical sequence," it is possible to have many different types of consecutive things: consecutive days, months, odd numbers, even numbers, etc. The list you have is consecutive, they are consecutive multiples of ten.

No. The concept of consecutive makes sense for integers but not for fractions. Fractions are infinitely dense. This means that there are infinitely many fractions between any two numbers - including between any two fractions. So, given one fraction, f1, there cannot be a "next" or "consecutive" fraction, f2, because there are an infinite number of fractions between f1 and f2.

There are countably infinite (Aleph-Null) of such numbers.

6

Nine of them. All consecutive integers have nine tenths between them.