answersLogoWhite

0


Verified answer

AWNSERS

A. JP=KP

C.XY and JK form four right angles

D. XY _I_ JK

F. m

User Avatar

katlynn cooper

Lvl 3
2y ago
This answer is:
User Avatar
User Avatar

katlynn cooper

Lvl 1
2y ago
for some reason it didnt let me type out the rest of F. but the rest is
Still have questions?
magnify glass
imp
Continue Learning about Other Math

A first step in the construction of a perpendicular bisector is to draw a n?

Open the compass to a little more than half the distance between the two points. Draw arcs from above the line to below the line from each end. This will look a little bit like an American football. The line that goes through the pointed ends of the football is the perpendicular bisector.


Select the equation that is modeled by the diagram below?

That will be difficult to do since there is no diagram below.


What is the perpendicular bisector equation of the line segment whose end points are at 7 3 and -6 1?

To solve this, four steps are needed:Find the midpoint of the line segment (X, Y) which is a point on the perpendicular bisectorFind the slope m for the line segment: m = change_in_y/change_in_xFind the slope m' of the perpendicular line; the slopes of the lines are related by mm' = -1 → m' = -1/mFind the equation of the perpendicular bisector using the slope-point equation for a line passing through point (X, Y) with slope m': y - Y = m'(x - X)Have a go before reading the solution below.--------------------------------------------------------------------The midpoint of (7, 3) and (-6, 1) is at ((7 + -6)/2, (3 + 1)/2) = (1/2, 2)The slope of the line segment is: m = change_in_y/change_in_x = (1 - 3)/(-6 - 7) = -2/-13 = 2/13The slope of the perpendicular bisector is m' = -1/m = -1/(2/13) = -13/2The equation of the perpendicular bisector passing through point (X, Y) = (1/2, 2) with slope m' = -13/2 is given by:y - Y = m'(x - Y)→ y - 2 = -13/2(x - 1/2)→ 4y - 8 = -26x + 13→ 4y + 26x = 21


Does perpendicular have parallel lines?

= parallel + perpendicular As such no, perpendicular lines do not naturally have parallel lines. However...connect the lines in the symbols below. ++ ++ And you'll have 4 perpendicular lines, and 4 parallel lines.


The diagram of the pentagon below displays all the lines of symmetry for the penteagon?

True

Related questions

In the diagram below xy is the perpendicular bisector of jk?

It could be, but without the diagram it is not possible to be certain.


In the diagram below rs is the perpendicular bisector of PQ. statements must be true Check all that apply.ing?

T is the midpoint of PQangle PTR = 90 degreesRS _l_ PQPT = QT


A first step in the construction of a perpendicular bisector is to draw a n?

Open the compass to a little more than half the distance between the two points. Draw arcs from above the line to below the line from each end. This will look a little bit like an American football. The line that goes through the pointed ends of the football is the perpendicular bisector.


What is a process you would use to create the perpendicular bisector to a segment AB using only an unmarked straightedge and an unmarked compass?

Open the compass to a width greater than half the length of AB.Place the compass point at A.Draw arcs above and below the line AB.Move the compass point to B WITHOUT changing the compass setting.Draw arcs above and below AB to intersect them at X and Y.Join XY.XY is the perpendicular bisector of AB.7. Celebrate the successful completion of the task!


How do you get a perpendicular bisector on a line segment?

Set a compass to draw a circle with a radius that's more than half the length of the line segment but less than the whole length.Put the compass point at one end of the segment and draw an arc above the middle of the segment and another below the middle of the segment.Put the compass point at the other end of the segment and again draw arcs above and below the middle of the segment, intersecting the first two arcs.Draw a line connecting the point where the two arcs intersect above the segment and the point where they intersect below the segment.That's your perpendicular bisector.


What is the perpendicular bisector equation of the line segment whose end points are at 7 3 and -6 1?

To solve this, four steps are needed:Find the midpoint of the line segment (X, Y) which is a point on the perpendicular bisectorFind the slope m for the line segment: m = change_in_y/change_in_xFind the slope m' of the perpendicular line; the slopes of the lines are related by mm' = -1 → m' = -1/mFind the equation of the perpendicular bisector using the slope-point equation for a line passing through point (X, Y) with slope m': y - Y = m'(x - X)Have a go before reading the solution below.--------------------------------------------------------------------The midpoint of (7, 3) and (-6, 1) is at ((7 + -6)/2, (3 + 1)/2) = (1/2, 2)The slope of the line segment is: m = change_in_y/change_in_x = (1 - 3)/(-6 - 7) = -2/-13 = 2/13The slope of the perpendicular bisector is m' = -1/m = -1/(2/13) = -13/2The equation of the perpendicular bisector passing through point (X, Y) = (1/2, 2) with slope m' = -13/2 is given by:y - Y = m'(x - Y)→ y - 2 = -13/2(x - 1/2)→ 4y - 8 = -26x + 13→ 4y + 26x = 21


Select the equation that is modeled by the diagram below?

That will be difficult to do since there is no diagram below.


Does perpendicular have parallel lines?

= parallel + perpendicular As such no, perpendicular lines do not naturally have parallel lines. However...connect the lines in the symbols below. ++ ++ And you'll have 4 perpendicular lines, and 4 parallel lines.


What are perpendicular rays?

Perpendicular rays are two rays that intersect one another to form four right angles. Below is an image that shows two perpendicular rays.


What are two perpendicular rays?

Perpendicular rays are two rays that intersect one another to form four right angles. Below is an image that shows two perpendicular rays.


What statement below is NOT part of an unstructured problem?

You did not include any 'statements below'.


Can you Show a diagram of the 3 branches of government?

There is a diagram at the related link below.