If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.
A number is divisible by 3 if the sum of its digits is divisible by 3.
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
9 is the largest digit and so there are no digits that are divisible by 9.
If the last 3 digits are divisible by 8 and the sum of the digits are divisible by 9.
No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
No it's not. For a number to be divisible by 9, the sumof the digits must also be divisible by 9. These digits add up to 17
4 and all of its multiples are divisible by 4. They end in even digits. No number that ends in an odd digit is divisible by 4.
9
No, 34,456,433 is not evenly divisible by 9. To confirm this, add up the digits. The sum of the digits is 32, which is not divisible by 9, so 34, 456,433 is not divisible by 9.
If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 5+1+8 = 14 and 14 is not divisible by 3. So 518 is not divisible by 3.
26 is not divisible by 9 because the sum of the digits is not divisible by
A number is divisible by 4 if the number formed by its last two digits is divisible by 4.Equivalently, halve the number formed by the last two digits. If the quotient is even, then the original number is divisible by 4.
Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.
All multiples of four are divisible by four.
sum of its digits is also divisible by 3.
A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 60 is 6 + 0 = 6, which is divisible by 3, so, yes, 60 is divisible by 3. 60 ÷ 3 = 20
If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 1+3+4+5+6 = 19 and 19 is not divisible by 3. So 13456 is not divisible by 3.
A number is divisible by 4 if and only if its last two digits are divisible by 4. For example, 53112 is divisible by 4, because the last two digits (12) are divisible by 4.
It is divisible by 2 because it ends in with four.It is divisible by 3 because the sum of its digits are divisible by three.It is divisible by 4 because the last two digits are divisible by four.It is divisible by 6 because it is divisible by both two and three.It is divisible by 9 because the sum of its digits are divisible by nine.The complete list of factors for 324 are:1, 2, 3, 4, 6, 9, 12, 18, and 27.
If the last 3 digits are divisible by 8, the number is divisible by 8.
No - any number divisible by 9 will have the sum of its digits divisible by 9.
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.