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Q: What are three consecutive integers of -363?

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There is no set of three consecutive integers for 187.

9240 is the product of the three consecutive integers 20, 21, and 22.

The sum of three consecutive odd integers, starting with N, is expressed as N + (N+2) + (N+4). If that sum is 363, then you have 3N + 6 = 363. Solve for N and you have 119.Since N (119) is odd, the answer and question are valid. (If N had been even, the question would have been invalid, and the answer would have been meaningless. This test is simply a sanity check.) The three numbers are 119, 121, and 123.

There is no set of three consecutive integers whose sum is 71.

There is no set of three consecutive integers for 106.

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

The sum of three consecutive integers is -72

find three consecutive integers whose sum is - 93

20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22

That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

There are no three consecutive odd integers who's sum equals 13.

There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.

Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.

Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.

No. There is no set of three consecutive even integers with a sum of 40.

Divide the sum of the three consecutive odd integers by 3: -3 /3 = -1. The smallest of these integers will be two less than -1 and the largest will be two more than -1, so the three consecutive odd integers will be -3, -1, and +1.

The three integers are 187, 188 and 189.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

The integers are -19, -18 and -17.

Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.

Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.

Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.

The three integers are 25, 26, and 27.