To check if 10,534,341 is divisible by 3, add the digits: 1 + 0 + 5 + 3 + 4 + 3 + 4 + 1 = 21, which is divisible by 3, so 10,534,341 is divisible by 3. For divisibility by 9, since 21 is not divisible by 9, the number is not divisible by 9. Lastly, since the last digit is 1 (an odd number), it is not divisible by 2. Therefore, 10,534,341 is divisible by 3 only.
its divisble by 2 9 3
2520
1, 3, 9, 27
No, but it is divisible by 9 and 2
yes for a number to be divisble by 3 you have to add the numbers together and see if you can divide it by 3 evenly 1+5+3= 9 9 can be divided by 3 evenly so that makes the number, 153 divisble by 3
its divisble by 2 9 3
No.
There are infinitely many numbers divisible by 2, 3, 5 and 9. One such is 900.
2520
No, because when something is divisible by 6, it is divisible by 2 or 3. This is divisible by 3, but not 2.
any number is divisible by another.. 7960/9=884.4444 not evenly divisble but divisible one quick way /math trick to know if a number is evenly divisble by 9 is add the integers in this case 7+9+6=22 2+2=4 so not evenly divisble by 9 however 180 1+8 is divisble by 9 171 (1+7+1) is evenly divisble by 9 171/9=19 13464 ==> 1+3+4+6+4=18 1+8=9 so evenly divisble by 9 13464/9=1496
202008 ÷ 9 = 22445 remainder 3
No. For example, 9 is divisible by 3 and 9, but not 6. Even numbers that are divisble by 3 and 9 are also divisble by 6.
1, 3, 9, 27
No, but it is divisible by 9 and 2
3 and 9 are both divisors of 621
No. The sum of the digits of 290 (ie 2+9+0 = 11) is not divisible by 3, so 290 is not. NB This rule only works for 3 and 9.