Yes. 117 is evenly divisible by nine.
117 divided by 9 = 13
Yes. 117 is evenly divisible by nine.
1, 3, 9, 13, 39, 117.
117
108, 117, 126, 135, 144, 153, 162, 171.
117 and 225, yes. The rest, no.
117 divided by 9 = 13
Yes. 117 is evenly divisible by nine.
1, 3, 9, 13, 39, 117.
No, 117 is only divisible by: 1, 3, 9, 13, 39, 117.
117
108, 117, 126, 135, 144, 153, 162, 171.
3, 9, 13, and 39.
No it doesn't because 9 times 13 is 117.
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117
109 is divisble by 9
The number which is exactly divisible by 9 should have its digits adding to equal 9. Its 1st digit should be subtracted by 1 from its 9th factor. For example: 2 x 9 = 18, with 1 + 8 = 9 and 2 - 1 = 1 from 18.