Yes, given that it is spelled exactly the same in both cases!
It is: 14/7 = 2/1 which is the same as 2
-1 + -2 is the same as -1 - 2. -1 - 2 = -3
-1/2 or 1/-2 but most commonly -(1/2) (They all are the same)
3 + -4 is the same as -4 + 3. (In the same way that 1 + 2 is the same as 2 + 1).
The digit indicate the facing direction of the runway. A single digit could be confusing. Ex: does 1 mean 01 or 10? Is 7 07 or 70. 07 is NNE and 70 is ENE.
there is cyclobut-1-ene but-2-yne but-1-yne 3-methylcycloprop-1-ene but-1,2-diene but-1,3-diene 2-methylcycloprop-1-ene and two more nameless ones, which have the line diagrams: /|\ \|/ and /_\
Unfortunately it is impossible to draw every structural isomer on word, therefore, I'd suggest looking it up in a book, or trying it yourself.isomers: are compounds with the same molecular formula but different structural shapes.
trans-1,3-dichloroprop-1-ene cis-1,3-dichloroprop-1-ene trans-1,2-dichloroprop-1-ene cis-1,2-dichloroprop-1-ene 1,1-dichloroprop-2-ene 1,1-dichloroprop-1-ene 1,2-dichloroprop-2-ene The acylclic isomers are. 1,1-dichlorocyclopropane cis-1,2-dichlorocyclopropane rans-1,2-dichlorocyclopropane
You get propane Also, if it existed, it would be prop-1-ene, but all propene is prop-1-ene, so no number is required.
acetone and acetaldehyde (1 molecule each).
There 4 isomers : 1) H2C=CHCH2CH3 => but-1-ene 2) CH3CH=CHCH3 => but-2-ene 3) (CH3)2C=CHCH3 => 2- methylpropene 4) CH2-CH2-CH2-CH2 => cyclobutane/cycloalkane. C4h8 has 3 isomers from the same homologous series and one that is not from the same homologous series.
The IUPAC name for C4H7Cl is (E)-1-chlorobut-2-ene.
Cis/Trans Isomerism occurs when there are two different groups on each side of the C=C bond. In But-2-ene the Carbons with a double bond are each bonded to one C and one H whereas, in But-1-ene one end is bonded to carbon and Hydrogen, and one end is bonded to two hydrogens. H [CH2]- CH3 \ / C=C But-1-ene: One end bonded to two Hydrogens, One end bonded / \ to 1 x Carbon, 1 x Hydrogen H [H] H H \ / C=C cis But-2-ene: Both ends of double bond are bonded to, 1 x Carbon / \ 1 x Hydrogen, and biggest elements on each side H3C CH3 (Carbon) are both on same side so cis or Z
Which of the alkyl chlorides undergoes dehydrohalogenation in the presence of a strong base to give pent-2-ene as the only alkene product - the choices are: A 2-chloropentane B 1-chloro-2-methylbutane C 1-chloropentane D 3-chloropentane The answer is: 3-chloropentane
This is hex3-ene-2-ol
Li metal in liquid NH3
The "but" part means there are 4 carbons. The "ene" means there is a double bond. The but-2-ene means the double bond is in position 2, soC-C=C-CThe 4-chloro means the Cl is on the 4th carbon. The question didn't say a number before the bromo, but we'll assume it is 1-bromo, so that means a bromine on the first carbon.Each C has 4 total bonds, and the rest are filled with hydrogen:Br-C-C=C-C-Cland fill out carbon 1 and 4 with 2 more H and the two middle C's with one H each.