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The sum itself is not a product - the product is the end result of a multiplication sum. The constituent parts of the question part of the sum are the multiplier and the multiplicand.
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∙ 13y ago
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What is the product of 3 and 5 multiplied the product of 4 and 2?
15 x 8 = 120
A number is multiplied by 3 if 2 is added to the product you get -4 what is the number?
-2 times 3 is -6 and add 2 you get -4
What is the product of -8 multiplied by -4?
-4
What is the product of 2 multiplied by negative two thirds?
2 x (-2/3) = -4/3 or -11/3
What 4 numbers multiplied makes 196?
As a product of its prime factors: 2*2*7*7 = 196
What is the product of 3 and 5 multiplied the product of 4 and 2?
15 x 8 = 120
What is the esimated product of 4 multiplied by 2?
Though its easy enough to know the answer of 4 x 2, the estimated product would be 10.
When 2 4 6 or 8 numbers are multiplied the product has a negative sign?
The answer will depend on the signs of the numbers being multiplied.
Is product is plus or minus?
if 2 positive numbers are multiplied, then the product is positive. if 2 negative numbers are multiplied, the product is positive. if a positive and a negative number are multiplied, the product is negative.
A number is multiplied by 3 if 2 is added to the product you get -4 what is the number?
-2 times 3 is -6 and add 2 you get -4
What is the product of 389 times 4?
The product of 389 multiplied by 4 is 1,556.
What is the product of -8 multiplied by -4?
-4
What is a square product?
2 factors multiplied and you get a product
What is the product of 2 multiplied by negative two thirds?
2 x (-2/3) = -4/3 or -11/3
What 4 numbers multiplied makes 196?
As a product of its prime factors: 2*2*7*7 = 196
What is 80 as a product of prime factorization?
Two to the fourth power multiplied by five.
A number is multiplied by 3 and then 4 is subtracted from the product then 2 us added to the difference if the result is 16 what is the number?
The number that when multiplied by 3, then 4 is subtracted and 2 added and the answer is 16 would be 6 .
