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Only if x is already an integer.
For any integer x, 2x + 2 will be an even integer.
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Find the three consecutive even integers such that if the largest integer is subtracted from 4 time the smallest the result is 6 more than twice the middle integer?
Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x. Then 4*(2x-2) - (2x+2) = 2*2x + 6 or 8x - 8 - 2x - 2 = 4x + 6 => 6x - 10 = 4x + 6 => 2x = 16 so that x = 8. So the numbers are 14, 16 and 18.
Which sequence of fx equals 2x plus 2 has integer input values?
f(x)=2x+2. Put in 0, 1/2, 1, 3/2, 2... and you will get integer values. That is for the domain. The numbers you get when you put that in are the range integral values.
Is an even number times any number always even?
YES Even Number by definition any integer that can be divided exactly by 2. To get an even number, multiply an integer by 2 or in mathematical statement it is 2n. An even number (2x) is multiplied to any number (y) is 2x (y). So, by associative principle of multiplication 2x(y) = 2 (x*y). If (x*y) now represents any integer then 2(x*y)= 2n. And 2n is an even number.
What is the two consecutive even integers whose sum is 90?
let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46
What two consecutive even positive integers equal 624?
Let x = first even integer then x + 2 = next even integer sum: x + x + 2 = 624 2x + 2 = 624 2x = 622 x = 311 x + 2 = 313 NOTICE the values are ODD not EVEN so there is no solution
If the sum of two consecutive even integers is -298 What are the integers?
-150, -148 To find these numbers set up an algebraic expression. The first even integer would be 2X and the next even integer would be 2X + 2 So, 2X + (2X+2) = -298 Solving for X, X = -75 So the first even integer would be 2*(-75) or -150 And the second even integer would be 2 + the first or 2+-150 or -148
Why is the sum of 2 even numbers always an even number?
If a is even then there is an integer x such that a = 2x If b is even then there is an integer y such that b = 2y Then a+b = 2x+2y = 2(x+y) ie 2 is a factor of a+b, that is, a+b is even.
If x 2 represents an even integer which expression must represent odd integer?
2x + 1
The reciprocal of an integer plus the reciprocal of two times the integer plus two equals two-thirds Find the integer?
1/x + 1/2x + 2 = 2/3; 3/2x = -4/3; -8x = 9 (2 + 1)/2x + 2 = 2/3 3 + 4x = 4x/3 9 + 12x = 4x 8x = -9 x = -1 1/8 which isn't an integer but fits the stated conditions If you're doing A+ the answer is 2.
Find the three consecutive even integers such that if the largest integer is subtracted from 4 time the smallest the result is 6 more than twice the middle integer?
Suppose the three integers are 2x-2, 2x and 2x+2 for some integer x. Then 4*(2x-2) - (2x+2) = 2*2x + 6 or 8x - 8 - 2x - 2 = 4x + 6 => 6x - 10 = 4x + 6 => 2x = 16 so that x = 8. So the numbers are 14, 16 and 18.
Which sequence of fx equals 2x plus 2 has integer input values?
f(x)=2x+2. Put in 0, 1/2, 1, 3/2, 2... and you will get integer values. That is for the domain. The numbers you get when you put that in are the range integral values.
Is an even number times any number always even?
YES Even Number by definition any integer that can be divided exactly by 2. To get an even number, multiply an integer by 2 or in mathematical statement it is 2n. An even number (2x) is multiplied to any number (y) is 2x (y). So, by associative principle of multiplication 2x(y) = 2 (x*y). If (x*y) now represents any integer then 2(x*y)= 2n. And 2n is an even number.
What are two consecutive even integers such that the smaller added to 3 times the larger gives a sum of 22?
Suppose n is the smaller integer. Since it is even, let n = 2x where x is an integer. Then the second integer is 2x+2 So 2x + 3*(2x+2) = 22 2x + 6x + 6 = 22 8x + 6 = 22 Subtract 6 from both sides: 8x = 16 Divide both sides by 4: 2x = 4 So the two integers are 2x and 2x+2 ie 4 and 6
What is the two consecutive even integers whose sum is 90?
let x = integer and x + 2 next consecutive even integer x +(x +2) = 90 2x + 2 = 90 2x + 88 x = 44 and x+2 = 46 44 and 46
What two consecutive even positive integers equal 624?
Let x = first even integer then x + 2 = next even integer sum: x + x + 2 = 624 2x + 2 = 624 2x = 622 x = 311 x + 2 = 313 NOTICE the values are ODD not EVEN so there is no solution
Is it possible to prove the square of even number is a even number using direct proof?
Yes. Any even number can be expressed as 2x (where x is an integer). (2x)2 = 4x2. We don't know exactly what x2 is, and we don't need to know, because we know that the square of any integer is also an integer, and any integer multiplied by 4 is an even number.
The product of two consecutive even integers is equal to 48 translate into an equation?
Suppose the first number is 2x (rather than x, so that you force it to be even), where x is an integer. Then the next (consecutive) even number is 2x+2. So the equation is: 2x * (2x+2) = 48
