Yes. It's a fine acceleration value, with proper units and dimensions.
It's roughly 31% of the acceleration of gravity on earth.
9.8 meters per second squared is the acceleration of gravity.
The sprinter's acceleration is 2 meters per second squared.
Acceleration is a change in velocity per unit of time. Velocity is distance (d) per unit of time (t). That makes acceleration distance per unit of time squared, or something like this:We have distance/time2, or d/t2Distance is commonly measured in meters, and time in seconds. This makes acceleration appear in meters per second per second, or meters per second squared, or m/sec2.m/s2meters per second squared
Use the formula for centripetal acceleration: velocity squared / radius.
The change in the velocity divided by time in meters per second squared.
3 meters per second squared
3 meters per second squared
3 meters per second squared i believe is the answer :-)
The answer is B - 3 meters per second squared
Acceleration is a change in speed, measured per second and so would be meters per second per second or meters per second squared.
(B) its a three meters per second squared.
3 meters per second squared or 3 meters per second per second.
b
g is a measurement of acceleration namely 9.8 meters per second squared. When there is an acceleration of 2g then simply multiply 9.8 meters per second squared times 2 or 19.6 meters per second squared.
Assuming you want the international units: time: second velocity: meters / second distance: meters acceleration: meters / second2
9.8 meters per second squared is the acceleration of gravity.
For every second of acceleration the velocity is increased by that acceleration.