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i got that question for homework and im in year 7

and i dont even know the answer :L

Yes. 715 is divisible by 5. To make it simple, ALL numbers ending with 5 or 0 are divisible by 5 (as long as they have no decimals or fractions)

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Yes, 715/5 = 143.

Q: Is 715 divisible by 5

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715 is divisible by any of its factors: 1,5,11,13,55,65,143,715 Evidence: 1x715=715 5x143=715 11x65=715 13x55=715

Pairs of positive integer factors of 715 are: 1 x 715 = 715 5 x 143 = 715 11 x 65 = 715 13 x 55 = 715 And their reverses.

5 x 11 x 13 = 715

715 = 5 x 11 x 13

We expand 715 into 7 hundreds, 1 ten, and 5 ones. This can be written as 7(100) + 1(10) + 5(1) = 715.

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715 is divisible by any of its factors: 1,5,11,13,55,65,143,715 Evidence: 1x715=715 5x143=715 11x65=715 13x55=715

nothing

143

143 of them.

The 8 factors of 715 are 1, 5, 11, 13, 55, 65, 143, and 715. The prime factors of 715 are 5, 11, and 13.

Pairs of positive integer factors of 715 are: 1 x 715 = 715 5 x 143 = 715 11 x 65 = 715 13 x 55 = 715 And their reverses.

Because 5 and 13 divide evenly into 715 with no remainder.

The factors of 715 are: 1, 5, 11, 13, 55, 65, 143, 715.

5 * 11 * 13 = 715

715 = 5 x 11 x 13

1, 5, 11, 13, 55, , 65, 143, and 715.

1, 5, 11, 13, 55, 65, 143, 715