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Q: Is 945 divisible by 3

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No. However, 945 is divisible by these numbers: 1, 3, 5, 7, 9, 15, 21, 27, 35, 45, 63, 105, 135, 189, 315, 945.

Yes. 945/9 = 105

945000, for example.

1, 3, 5, 7, 9, 15, 21, 27, 35, 45, 63, 105, 135, 189, 315, 945.

The number 945 is divisible by 3,7,5 and 9. An easy way to determine what number is divisible by a set of numbers is to multiply all the numbers in the set.3*9*7*5=945 The LCM is 315.

945

945

They are members of the infinite set of numbers of the form 945*k where k is an integer. Since the set is infinite, it is not possible to list them.

The multiples of 105 are divisible by 105, namely:105, 210, 315, 420, 525, 630, 735, 840, 945, 1050, ...105 is divisible by its factors: 1, 3, 5, 7, 15, 35, 105

As a product of its prime factors: 3*3*3*5*7 = 945

945 315,3 105,3,3 35,3,3,3 7,5,3,3,3 3 x 3 x 3 x 5 x 7 = 945

For 945: 3, 5 and 7 For 441: 3 and 7

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