No.
123
k = x y x = k/y
K= 18.666666
The value of k is 0
I am assuming that k is the constant of proportionality so that f = k*a*t/b2 = 3*4*6/22 = 18
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
Yes, the equation K + Br2 = KBr is a balanced chemical equation. For example, 2 K + Br2 = 2 KBr is one and another balance chemical equation is Fe + Cl2 = FeCl3.
Balanced:2 K + Br2 ----> 2 KBr
This is a halogen single replacement reaction, in which the more active chlorine will take the place of the bromine in the potassium bromide. 2KBr + Cl2 --> 2KCl + Br2
2KBr + 2H2O----->2KOH + Br2 + H2(g) this is the reaction in electrolysis of KBr in aqueous solution
2 K + Br2 -> 2 Kbr
The salt potassium bromide. The chemical equation is 2 K + Br2 -> 2 KBr.
First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
There are two atoms in one molecule KBr. One atom of potassium (K) and one atom of bromine (Br).
cl2 kbr---kcl br2i think u mean balance it right ^^;here u have cl2 kbr---kcl br2 so what u do iscl2 kbr---kcl br2cl=2 cl=1k=1 k=1br=1 br=2so u need to balance that ...u need to add (2) to kbr and add (2) to kcl so that u have Cl2 (2)KBr ----(2)KCl Br2 hope that will help ^^ so now u have them balanced by adding 2 in front of kbr that means u r multiplying them by 2 so that K is going to be k=2 and br is going to be br=2 and u r doing that because there is br =1 on one side and the other side there is br=2 and u need them balanced. By adding 2 to kcl means that the other k now is k=2 so as cl. hope its helpful ^____~
The molecular equation is 2KOH(aq) + CoBr2(aq) ==> 2KBr(aq) + Co(OH)2(s)The spectator ions are K^+ and Br^-
K j equals j when K is 1 or j is 0.