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Is a number divisible by 3 if its last digit is divisible by 3?
Wiki User
∙ 11y ago
No. Consider 13 or 23.
Wiki User
∙ 11y ago
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Is a number divisible by 3 if its the last digit is divisible by 3?
no
What is a 4 digit number that is divisible 3 and 9?
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
What is a 3 digit number that is divisible by 1?
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
Is the number 432 divisible by 2 3 5 6 9 10?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
How many 3 digit numbers will be there which are divisible by 19?
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
Is a number divisible by 3 if its the last digit is divisible by 3?
no
What is the converse inverse and contrapositive If every digit of a number is divisible by 3 then the number is divisible by 3?
Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.
Is 552 divisible by 6?
yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6
What is a 4 digit number that is divisible 3 and 9?
All 4 digit numbers that are divisible by 9 are also divisible by 3. The first is 1008 and the last is 9999.
Is 998873 divisible by 2?
no, as it is an odd number. (3 as the last digit)
Is 144 divisible by 2 3 4 5 6 9 or 10?
144 is divisible by 2, 3, 4, 6, 9 and not divisible by 5 or 10.Divisible by 2The whole number is divisible by 2 if the number is even which is shown by the last digit being divisible by 2. The last digit of 144 is 4 and 4 is divisible by 2, thus 144 is divisible by 2.Divisible by 3The number is divisible by 3 if the sum of its digits is also divisible by 3. Sum of the digits of 144 is 1+4+4 = 9 which is divisible by 3, thus 144 is divisible by 3Divisible by 4The number is divisible by 4 is the last two digits is also divisible by 4. Last two digits of 144 are 44 which are divisible by 4, thus 144 is divisible by 4An alternative test: If the last digit plus twice the preceding digit is divisible by 4 then the whole number is divisible by 4.For 144, last digit + twice preceding digit is 4+2x4 = 12 which is divisible by 4, so 144 is divisible by 4Divisible by 5If the last digit is 0 or 5 then the number is divisible by 5 Last digit of 144 is 4 which is neither 0 nor 5, thus 144 is not divisible by 5Divisible by 6To be divisible by 6, the number must be divisible by both of 2 and 3. 144 is divisible by both 2 and 3 (see above), thus 144 is divisible by 6Divisible by 9If the sum of the digits of the number is divisible by 9, then the original number is divisible by 9. For 144, 1+4+4 = 9 which is divisible by 9, thus 144 is divisible by 9Divisible by 10To be divisible by 10, the last digit must be 0. The last digit of 144 is 4 which is not 0, thus 144 is not divisible by 10
What is a 3 digit number that is divisible by 1?
a 3 digit number that is divisible by on is a three digit number that is a multiple of one.
How many three digits natural numbers are divisible by 4?
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
Is the number 432 divisible by 2 3 5 6 9 10?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
What is the divisiable rule for 3 and 2?
The divisible rule for 2 is if the last digit of the number is 0,2,4,6, or 8. The divisible rule for 3 is if the last 2 digits of the number is divisible by 3,03,06,09,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96, or 99.
How many 3 digit numbers will be there which are divisible by 19?
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
Is the number 26 divisible by 2 3 5 or 9 How do you know?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.
