FALSE!
'v' generally refers to final velocity 'u' generally refers to initial velocity (because not everything starts from a motionless state, where 'u' would equal zero) It is better to annotate initial velocity as v0 (v-sub-zero or simply v-zero).
Find out the time using speed and acceleration, (time=speed/acceleration) and then use it to find out uniform velocity. From that find out uniform acceleration. (as uniform acceleration is equal changes of velocity over equal intervals of time)
Acceleration.
The formula is vf = v0 + at It means that the (final velocity) is equal to the (initial velocity) plus (acceleration multiplied by elapsed time). We can rearrange the equation to look like t = (vf - v0) / a Since initial velocity is zero, and we are assuming that Earth has acceleration due to gravity of 9.8 m/s2, we can sub the values into the equation and get t = (147 m/s) / (9.8 m/s2) t = 15 s So it will take 15 seconds
Acceleration is the derivative of velocity (a=dv/dt). If you are not familiar with calculus then it would be sufficient to say that the slope of the line tangent to the graph, only touches at one point, is equal to the instantaneous acceleration.
No, It is the average velocity.
Yes, sort of. At least, that's the units used. The actual definition of acceleration is: a = dv/dt In other words, the rate at which velocity changes. In the case of constant acceleration, that would be equal to a change in velocity, divided by the time interval during which this change takes place. In the case of non-constant acceleration, the acceleration, or rate of change of velocity, can of course change from one moment to another.
Average Acceleration can be verbally defined as the change in velocity in a certain change in time... More simply put: Average Acceleration = (Final Velocity - Initial Velocity) / (Final Time - Initial Time)
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
It's equal to the change in velocity (final velocity - initial velocity).
It doesn't "affect" it. Acceleration is DEFINED as (delta v) / (delta t), or change in velocity divided by the time elapsed; so whenever you have a delta-v, you'll have an acceleration (the amount of which also depends on the time elapsed).
That's the velocity at any time.
Velocity is equal to distance traveled divided by the time it took to travel. v = d / t Velocity also equals the initial velocity plus the acceleration times time. v = v1 + a(t)
If, as you say, its acceleration is "constant", then the average is exactly equal to that constant.
Yes acceleration equals velocity divided by time i.e a=v/t and it's S.I unit is m/s2
It equals an undefined entity. The average acceleration of an object equals the CHANGE in velocity divided by the time interval. The term "change in velocity" is not the same as the term "velocity", "average velocity", or "instantaneous velocity".
I'm assuming you are not talking about constant acceleration, which in itself iscontinuous. If you are talking about constant (meaning it's just a number, and not a function itself) acceleration, than just use the formula:v = i + at, wherev = velocity, i = initial velocity, a = acceleration, and t = timeOtherwise, you need to have some calculus knowledge. A velocity function is just the antiderivative (integral) of an acceleration function.Say, acceleration was given as:a = 2ttake the integral of thatv =∫ 2t dt = (2/2)t2+c =t2+cIn this case, the c is the initial velocity.Example:An object moves with an acceleration determined by a=t+3 (in m/s^2). Find the velocity of the object after 10 seconds have passed, given that the object has an initial velocity of 2 m/s.a = t + 3v =∫( t + 3) dt = (1/2)t2 + 3t + c, with c being initial velocityv(10 seconds) = (1/2)(10)2 + 3(10) + (2) = 82 m/s