2520
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
There are only three proper factors of 81; they are 3, 9 and 27.81 is also divisible by 1 and by itself, but mathematicians regard these as improper factors because they are trivial. Every natural number is divisible by itself and by unity.
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
Every number is divisible by any non-zero number. Furthermore, it is evenly divisible by 3.
Because 3 is larger than 1. A number can't be divisible by a larger number.
Every number is divisible by 1. Including negative numbers, that's an infinite list. There is no smallest.
Every number is divisible by any non-zero number.937 is a prime.
78 is evenly divisible by 1, 2, 3, and 13.
Any number divisible by 3 has digits that add up to a multiple of 3. Adding a 1 to any of these digits or inserting a 1 anywhere in the number would make it divisible by 3.
Yes. Every number is divisible by itself or 1.
Every number except zero is divisible by 1 but the result won't always necessarily be a whole number or a positive number.
2520
Every number is divisible by any non-zero number. However, 10 is not evenly divisible by 753.
No. 1/2 is a rational number but it is not a natural number.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
No. A prime number (or a prime) is a natural number which has exactly two distinct natural number divisors: 1 and itself. 13 is only divisible by 1 and itself (13). 14 is also divisible by 2 and 7, therefor is not a prime number.