Yes, draw a 2 x 7 rectangle.
10 uints
No, but I can tell you that an 8 x 8 square has an area of 64 and a perimeter of 32.
write an algorithm and draw a flow chart to find perimeter of a square
It's impossible. The largest area for a rectangle with perimeter of 6 is 2.25, a perfect square with a length of 1.5 for each side. Any other combination yields a smaller area.
A rectangle with sides of 3 and 4 units will meet the requirements.
Yes.
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
10 uints
To draw a shape with the same area and perimeter, decide what shape you want to draw, then take the equations for area and perimeter and make them equal, and then solve what the various side lengths have to be. For instance, the area of a square is L2 where L is the side length, and the perimeter of a square is Lx4 We want them equal, so L2=Lx4 Dividing both sides by L gives us L=4, so if I draw a square with side length 4, it will have the same area and perimeter.
No, but I can tell you that an 8 x 8 square has an area of 64 and a perimeter of 32.
write an algorithm and draw a flow chart to find perimeter of a square
10 ------------------------------- | | 0.5 -------------------------------
Yes. Make the length of each side 1/4 of the desired perimeter.
0.000...1cm length on two sides. 19.999...9cm length on the other two.
Draw a rectangle with 2 sides 5 units long and 2 sides 4 units long
9X2
Assuming no fractional dimensions, least possible area would be a rectangle measuring 1cm x 9cm. Area increases to a maximum of 25 sq cm when shape is square, ie 5cm x 5cm.