One in eight, or 12.5%.
Probability of not 8 heads = 1- Prob of 8 heads. Prob of 8 heads = 0.5^8 = 0.003906 Prob of not 8 heads= 1- 0.003906 = 0.99604
The probability of flipping a heads is 1/2 and the probability of rolling a 6 is 1/6. By the laws of probability it would be logical to multiply them together, (1/2)(1/6) thus the answer being 1/12 with is roughly eight percent.
Assuming we want two tails exactly, the possible options to get them are: TTH, THT and HTT. They are three choices out of the eight available, which is a probability of 3/8, 0.375 or 37.5%.
The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
The probability is 0.
Assuming the numbers are 1-6, the probability is 0.
The probability is 61.538 if you are starting with a fresh deck and it is the first draw.
It is 1/13.
I'm assuming that a "1-8 spinner" is similar to an eight-sided die, so the probability of spinning a 10 is zero. When throwing dice, or flipping a coin, etc., each outcome is independent. That is, it's not influenced by the previous outcome(s). So if you get three 8s in a row then the probability of getting an 8 on the fourth throw remains at 1/8. The probability of an 8 on each and every throw is always 1/8.
Assuming that there are an equal number of even and odd faces on the eight-sided die, then the probability of rolling an even number is simply 4 in 8, or 1 in 2, or 0.5.
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
Number of cards in a deck =52 Number of cards that are spade =13 Number of cards that are eight =4 Number of cards that are spade and eight =1 Probability that the card drawn is a spade or an eight = 13/52+4/52 -1/52 =16/52 or 4/13
I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
It is 0.375
the answer is 2/13
There are 4 eight cards, and 12 face cards including the Jack, Queen and King.So 4 +12 =16, which is the number of eight and face cards you have in a standard deck.To find the probability, we will have 16/52 = 0.308
The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%
For any particular card, (eg an 8) there are 4 such cards in a pack of 52. So the probability of drawing one of these is 4/52, or 1 in 13. After restoring the card to the pack and doing it again the probability is a further 1/13. So the overall probability of doing the 2 things in succession is 1/13 x 1/13 = 1/169.