False. Consider 4, itself.
Three is a prime number and isn't divisible by any whole number * * * * * True, but irrelevant to the question. Any number that is divisible by 10 MUST be divisible by 5. Therefore there are no such numbers.
4 is divisible by 2 but not by 6
False. You can only replace it with a number from the domain of the function.
4 divides 4 (once), but 4 is not divisible by 8. ■
You are an Idiot dude. there is no such value
They're ALL divisible by 1... and themselves !
These numbers are not evenly divisible by 6: Any number smaller than 6. Any odd number (not divisible by 2). Any number not divisible by 3. If a number is divisible by both 2 and 3, it is divisible by 6.
Yes. Any number is divisible by any other number.
Yes, any number is divisible by any other number
False. Factors divide evenly with no remainder.
An integer is any whole number, so the answer would be true.
Any number is divisible by any other number. This does not mean the answer will be a whole number.
There can't be any such number.' 4 ' itself is divisible by 2, so any number divisible by 4 must also be divisible by 2.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
A number that is divisible by 2 is not always evenly divisible by 6. It must also be divisible by 3, and must not be smaller than 6. The numbers 2, 4, 8, 10, 14, 16, 20, 22, 26, and 28 etc. are all divisible by 2 but not (evenly) by 6. The opposite is true, though. Any number divisible by 6 is also divisible by 2.
Any number is divisible by any number. There is no number that is divisible by any number into a whole number with no remainder other than 0.
True. Every one is a sum of 0 and itself!
There is no such number. Since 6 is divisible by 3, then any number that is divisible by 6 automatically has to be divisible by 3.
Yes, it's true. 3 is one of the factors of 6, so any number that has six as a factor also has 3 as a factor.
Yes. Data can be any form of information.
The sum of the digits of the number will add to a number that's divisible by nine. For example, 99 -> 9+9 -> 18. 18 is divisible by nine, thus 99 is. Any whole number that's divisible by nine will have its digits add up like this, and any whole number whose digits add up like this will be divisible by nine.
It is divisible by any of its factors