Yes, it is true.
A rational number is any number that can be expressed as a fraction. It becomes meaningless or undefined when the lower number, the denominator, its 0 (zero)
Whenever you solve a rational equation you must make sure the result obtained for an answer does not allow the denominator of one of the rational expressions to assume a value of ZERO, as division by zero is undefined and therefore prohibited. For example if we have 2x/(x-3) =(x2 -9x)/ x when we multiply out by x(x-3) we get 2x(x) = (x2 -9x)(x-3) so 2x2 = x(x-9)(x-3) 2x2 = x(x2 - 12x + 27) 2x2 = x3 - 12x2 + 27x so 0 = x3 - 14x2 + 27x 0 = x(x2 - 14x + 27) so solutions are 0 and 7 + √22 and 7 -√22 but 0 makes right hand side expression have zero in denominator so it is not a solution. We actually have to look at all obtained solutions to be sure they ae not extraneous. Suppose we had obtained a 3 for a solution. That would make the left side denominator equal zero and we would have to dismiss that, if 3 was obtained. The two irrational solutions we have obtained are genuine solutions as neither introduces a zero to a denominator
A power with a rational exponent m/n in lowest terms satisfies : whenever this makes sense.
Rational and irrational numbers are real numbers. A complex number is represented by a+bi where a and b are real numbers. Zero is a real number therefore any real number is also complex whenever b=0
because a fraction means the numerator divided by the denominator. whenever you take zero and divide it by something you will always get zero Ex. 0/4 = 0 0/2935871238957 = 0 0/109 = 0
True
A rational expression is not defined whenever the denominator of the expression equals zero. These will be the roots or zeros of the denominator.
False
A rational number is any number that can be expressed as a fraction. It becomes meaningless or undefined when the lower number, the denominator, its 0 (zero)
false
No. 0/3 is well defined.
Whenever we are dealing with rational fractions.
Whenever you solve a rational equation you must make sure the result obtained for an answer does not allow the denominator of one of the rational expressions to assume a value of ZERO, as division by zero is undefined and therefore prohibited. For example if we have 2x/(x-3) =(x2 -9x)/ x when we multiply out by x(x-3) we get 2x(x) = (x2 -9x)(x-3) so 2x2 = x(x-9)(x-3) 2x2 = x(x2 - 12x + 27) 2x2 = x3 - 12x2 + 27x so 0 = x3 - 14x2 + 27x 0 = x(x2 - 14x + 27) so solutions are 0 and 7 + √22 and 7 -√22 but 0 makes right hand side expression have zero in denominator so it is not a solution. We actually have to look at all obtained solutions to be sure they ae not extraneous. Suppose we had obtained a 3 for a solution. That would make the left side denominator equal zero and we would have to dismiss that, if 3 was obtained. The two irrational solutions we have obtained are genuine solutions as neither introduces a zero to a denominator
Yes it does: whenever you find an equivalent fraction.
cause whenever he sees little boys he makes that facial expression
-Pi is irrational, because it does not terminate or repeat. Whenever you multiply an irrational number by a rational number (-1), the result is an irrational number.
Since any number divided by zero is undefined, a computer cannot base a calculation on this. Whenever a program attempts to divide by zero, this error is generated.