If you know the initial and final velocity you can determine the acceleration (Velocity final- Velocity initial)/time = acceleration This can also be seen by integrating the acceleration. In this case lets assume acceleration is constant, then: acceleration=C Integration from time=initial to time=final gives C*(time final-time initial)=velocity final-velocity initial This integration scheme can also work if acceleration is not constant. In this case you must know how acceleration or velocity changes with time.
Use the formula Acceleration = (final velosity - initial velocity)/ time.
Distance = |(v2 - u2)/(2a)| where initial velocity = u final velocity = v accelaration = s
One formula that can be used - assuming constant acceleration, of course! - is vf2 = vi2 + 2as, where vf is the final speed, vi is the initial speed, a is the acceleration and s is the distance. In your case, solve for final velocity.
This can't be done with just final velocity and time. You need to know the acceleration. If you do know the acceleration, multiply it by the time, and subtract that from the final velocity.
Assuming you also know the final velocity and acceleration over the displacement then the initial velocity is Vinitial = (Vfinal2 - 2*acceleration*displacement)0.5
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
Acceleration is the rate of change of velocity per time, so to get velocity, multiply (acceleration)*(time). This will give the change in velocity over the specific amount of time. You must add the initial velocity to get the final velocity, so we have the formula: Vf = Vo + a*t, where Vo is the initial velocity. This means that you can rearrange to get Vo = Vf - a*t
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
You should use the formula you learned for just exactly this situation.V = V0 + a tFinal speed = (initial speed) + (acceleration) x (time)
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
V= vi + at
That's truly a tough one. Particularly if you've been skipping the homework, or notpaying attention in class.Final velocity = (Initial velocity) + (acceleration) x (time).Surely, you can massage this around to solve it for 'time'.
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
(acceleration X time) + beginning velocity = final speed
V= v0 + kt where k is the constant acceleration and v0 is the initial velocity.
vf2 = vi2 + 2ad, where vf is final velocity, vi is initial velocity, a is acceleration, and d is displacement. Solve for a.vf = vi + at, where t is time time. Solve for a.
If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer
since time is given you are done
As we responded last time you posted the same question:You should use the formula you learned for just exactly this situation.V = V0 + a tFinal speed = (initial speed) + (acceleration) x (time)
You need velocity at two points in time, and the acceleration must be constant. If the initial velocity is u ms-1 and the final velocity is v ms-1, and the time interval is t then t = (v - u)/a s.
If you have an initial and final velocity and time you can figure it out with this equation, Vf squared=Vi squared1/2a(t squared) If you don't have those you cannot find acceleration. However the acceleration on Earth is a constant -9.81
Acceleration is the rate of change in velocity.
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time